Differentiation — Flashcards
ICSE · Class 11 · Mathematics
32 flashcards for Differentiation (ICSE Class 11 Mathematics) to test yourself on key terms and facts. Sample: "Find the derivative of f(x) = x at x = 1"
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Find the derivative of f(x) = x at x = 1 using first principle.
Answer
Step 1: Use f'(x) = lim h→0 [f(x+h) - f(x)] / h. Step 2: Here, f(1+h) = 1+h and f(1) = 1. Step 3: f'(1) = lim h→0 [(1+h) - 1] / h = lim h→0 [h/h] = lim h→0 [1] = 1. Answer: 1…
Find the derivative of f(x) = 99x at x = 100 using first principle.
Answer
Step 1: Use f'(x) = lim h→0 [f(x+h) - f(x)] / h. Step 2: f(100+h) = 99(100+h) and f(100) = 9900. Step 3: f'(100) = lim h→0 [99(100+h) - 9900] / h = lim h→0 [99h/h] = 99. Answer: 99…
Solve: If f(x) = x^2 - 2, find f'(10).
Answer
Step 1: Use f'(x) = lim h→0 [f(x+h) - f(x)] / h. Step 2: f(10+h) = (10+h)^2 - 2 = 100 + 20h + h^2 - 2. Step 3: f(10) = 10^2 - 2 = 98. Step 4: f'(10) = lim h→0 [(100 + 20h + h^2 - 2) - 98] / h = lim h→…
Solve: If f(x) = kx^2, find f'(2).
Answer
Step 1: Use f'(x) = lim h→0 [f(x+h) - f(x)] / h. Step 2: f(2+h) = k(2+h)^2 = k(4 + 4h + h^2). Step 3: f(2) = 4k. Step 4: f'(2) = lim h→0 [k(4 + 4h + h^2) - 4k] / h = lim h→0 [k(4h + h^2)]/h = lim h→0 …
Solve: For f(x) = 2x^2 + 3x - 5, find f'(-1).
Answer
Step 1: Use f'(x) = lim h→0 [f(x+h) - f(x)] / h. Step 2: f(-1+h) = 2(-1+h)^2 + 3(-1+h) - 5. Step 3: Expand: 2(1 - 2h + h^2) - 3 + 3h - 5 = -6 - h + 2h^2. Step 4: f(-1) = 2(1) - 3 - 5 = -6. Step 5: f'(…
Apply the result for f(x) = 2x^2 + 3x - 5 to find f'(0), then verify f'(0) + 3f'(-1).
Answer
Step 1: Differentiate f(x) = 2x^2 + 3x - 5. Step 2: f'(x) = 4x + 3. Step 3: f'(0) = 3. Step 4: From the previous result, f'(-1) = -1. Step 5: f'(0) + 3f'(-1) = 3 + 3(-1) = 0. Answer: f'(0) = 3 and f'(…
Find the derivative of f(x) = sin x at x = 0 using first principle.
Answer
Step 1: f'(0) = lim h→0 [sin(0+h) - sin 0] / h. Step 2: This becomes lim h→0 [sin h / h]. Step 3: The limit equals 1. Answer: 1…
Find the derivative of f(x) = cos 2x at x = π/2 using first principle.
Answer
Step 1: f'(π/2) = lim h→0 [cos(2(π/2 + h)) - cos(π)] / h. Step 2: This becomes lim h→0 [cos(π + 2h) + 1] / h. Step 3: Since cos(π + 2h) = -cos 2h, the expression is lim h→0 [1 - cos 2h] / h. Step 4: T…
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