Mass- Energy Equivalence: Nuclear Binding Energy — Practice Quiz
ICSE · Class 12 · Physics
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Quick Quiz: Mass- Energy Equivalence: Nuclear Binding Energy
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A deuteron has mass defect 0.002388 u. Find its binding energy in MeV using 1 u c^2 = 931.5 MeV.
A free proton and free neutron form a deuteron and 2.224 MeV is liberated. Find the binding energy per nucleon of the deuteron.
A 2.26 MeV gamma photon produces an electron-positron pair. Find the total kinetic energy shared by the two particles after pair production.
An electron-positron pair annihilates after a head-on collision and the total released energy is 1.02 MeV. If two photons are produced, what is the energy of each photon?
Sample Questions
A gamma photon has energy 0.80 MeV and strikes matter. Which effect can occur instead of pair production?
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Photoelectric or Compton effect
Pair production needs at least 1.02 MeV. A photon of 0.80 MeV is below threshold, so it can cause photoelectric effect or Compton effect, not pair production.
In pair production, a gamma photon of 3.02 MeV creates an electron-positron pair. What is the excess energy available as kinetic energy?
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2.00 MeV
The threshold for pair production is 1.02 MeV. Excess energy = 3.02 - 1.02 = 2.00 MeV. This becomes kinetic energy of the electron and positron.
A deuteron is disintegrated by a gamma-ray photon. What is the minimum photon energy needed?
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2.224 MeV
The binding energy of a deuteron is 2.224 MeV. A gamma-ray must supply at least this much energy to separate the proton and neutron.
A nucleus has 26 protons, 30 neutrons and nuclear mass 55.934939 u. Using mp = 1.007825 u and mn = 1.008665 u, find its mass defect in u.
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0.528461 u
Mass of free nucleons = 26 × 1.007825 + 30 × 1.008665 = 56.463400 u. Mass defect = 56.463400 - 55.934939 = 0.528461 u.
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