Moving Charges and Magnetic Field
ICSE · Class 12 · Physics
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A long straight wire carries a current of 10 A. What is the magnitude of the magnetic field at a distance of 5 cm from the wire? (μ₀/2π = 2 × 10⁻⁷ T m A⁻¹)
According to Biot-Savart's Law, the magnetic field dB due to a current element Idl at a distance r is proportional to:
A circular coil of 50 turns, radius 0.1 m carries a current of 2 A. What is the magnetic field at the centre of the coil? (μ₀ = 4π × 10⁻⁷ T m A⁻¹)
A proton moves with velocity 10⁶ m/s perpendicular to a uniform magnetic field of 0.5 T. What is the radius of its circular path? (mass of proton = 1.67 × 10⁻²⁷ kg, charge = 1.6 × 10⁻¹⁹ C)
Sample Questions
Oersted's experiment demonstrated which of the following?
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A current-carrying conductor produces a magnetic field around it
Step 1: In Oersted's 1820 experiment, a compass needle was placed near a current-carrying wire. Step 2: When current flowed, the needle deflected, showing a magnetic field was created around the wire. Step 3: When current was reversed, the needle deflected in the opposite direction. This proved that moving charges (electric current) produce magnetic fields. Option A is wrong – a stationary charge produces only an electric field, not magnetic. Option C describes electromagnetic induction (Faraday), not Oersted. Option D is also Faraday's law.
According to Ampere's Circuital Law, the line integral of the magnetic field B around a closed path is equal to:
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μ₀ times the current enclosed by the path
Step 1: Ampere's Circuital Law states: ∮ B·dl = μ₀I, where I is the net current threading through the area enclosed by the closed path. Step 2: μ₀ is the permeability of free space (4π × 10⁻⁷ N A⁻²). Step 3: Only the current enclosed by the chosen path matters, not the total current in the entire circuit. Option B is wrong as ε₀ is the electric permittivity used in Gauss's law for electric fields. Option C is wrong because it says 'total current' not 'enclosed current'. Option D introduces μ₀ε₀ which appears in electromagnetic wave equations.
When a charged particle moves parallel to a magnetic field, the magnetic force acting on it is:
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Zero
Step 1: The magnetic force on a moving charge is given by F = qvB sinθ, where θ is the angle between velocity and magnetic field. Step 2: When the particle moves parallel to the field, θ = 0°. Step 3: F = qvB sin0° = qvB × 0 = 0. The force is zero. The particle moves in a straight line without any deflection. Option A (maximum) corresponds to θ = 90°. Option C gives the maximum force formula. Option D is dimensionally incorrect.
The SI unit of magnetic field (B) is Tesla. Which of the following is an equivalent expression for 1 Tesla?
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1 N A⁻¹ m⁻¹
Step 1: From the force formula F = qvB sinθ, we can write B = F / (qv sinθ). Step 2: Units of B = Newton / (Coulomb × m/s) = N / (A·s × m/s) = N / (A·m). Step 3: So B = N A⁻¹ m⁻¹. This is also equal to 1 Wb m⁻². Step 4: 1 T = 1 N A⁻¹ m⁻¹ = 1 Wb m⁻². Options B, C, D have incorrect arrangements of the units – in B and D, A appears in numerator (positive power), and in C the length unit is in numerator instead of denominator.
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