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Practice Quiz

Nuclear Fission and Nuclear Fusion: Source of Energy

ICSE · Class 12 · Physics

Practice quiz for Nuclear Fission and Nuclear Fusion: Source of Energy — ICSE Class 12 Physics. MCQs and questions with answers to test your preparation.

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A step-by-step diagram illustrating the process of nuclear fission, specifically a chain reaction initiated by a neutron striking a Uranium-235 nucleus, leading to the release of energy and more neutr
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Quick Quiz: Nuclear Fission and Nuclear Fusion: Source of Energy

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1

A U-235 fission event releases 200 MeV of energy. If a reactor produces 320 MW, what is the fission rate per second?

2

A 1 g sample of U-235 is fully fissioned and each fission releases 200 MeV. How much energy is released in joules?

3

A 1000 MW reactor operates at 80% efficiency for 5 years and consumes only U-235 by fission. If each fission releases 200 MeV, what initial mass of U-235 was present?

4

A U-235 reactor uses 2 kg of fuel in 30 days. If each fission gives 185 MeV of usable energy, what is the power output of the reactor?

69 Questions·
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Sample Questions

1multiple choice
3 marks

A 50 kg uranium bomb releases 2.5 × 10^28 MeV. What is this energy equivalent in tons of TNT?

Show answer

20,000 tons of TNT

The stated equivalence for 50 kg uranium is 2.5 × 10^28 MeV, which corresponds to about 20,000 tons of TNT. This also matches the energy scale of large fission explosions.

2multiple choice
3 marks

A reactor produces 144 × 10^10 J of useful energy in 1 hour with 10% efficiency. What mass loss corresponds to the total energy released in the reactor during that hour?

Show answer

0.16 g

Useful energy = 144 × 10^10 J. At 10% efficiency, total released energy = 10 times this = 144 × 10^11 J. Using E = mc^2, m = 144 × 10^11 / (3 × 10^8)^2 = 0.16 g.

3multiple choice
3 marks

A plutonium-239 sample of 1 kg undergoes complete fission, and each fission releases 180 MeV. How much total energy is released in MeV?

Show answer

4.54 × 10^26 MeV

1 kg of Pu-239 contains (6.02 × 10^23 / 239) × 1000 = 2.52 × 10^24 atoms. Multiply by 180 MeV per fission to get 4.54 × 10^26 MeV.

4multiple choice
3 marks

A 2 kg sample of U-235 contains how many atoms?

Show answer

5.12 × 10^24 atoms

1 mole of U-235 has 6.02 × 10^23 atoms in 235 g. So 2000 g contains (6.02 × 10^23 / 235) × 2000 = 5.12 × 10^24 atoms.

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Frequently Asked Questions

What are the important topics in Nuclear Fission and Nuclear Fusion: Source of Energy for ICSE Class 12 Physics?
Nuclear Fission and Nuclear Fusion: Source of Energy covers several key topics that are frequently asked in ICSE Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Nuclear Fission and Nuclear Fusion: Source of Energy — ICSE Class 12 Physics?
Understand the core concepts first, then work through the 69 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

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