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Junction Diodes

ICSE · Class 12 · Physics

Practice quiz for Junction Diodes — ICSE Class 12 Physics. MCQs and questions with answers to test your preparation.

69 questions42 flashcards5 concepts

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A step-by-step diagram illustrating the formation of a p-n junction. Show a p-type and n-type semiconductor brought into contact, followed by the diffusion of majority carriers, the formation of immob
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Quick Quiz: Junction Diodes

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1

A silicon Zener diode has a depletion width of 1.0 × 10^-6 m and a reverse bias of 3 V across it. What is the electric field across the junction?

2

A Zener regulator has input voltage 16.8 V, Zener voltage 12 V, load current 12 mA, and Zener current 20 mA. What series resistance is required?

3

A full-wave rectifier has a peak output voltage of 18 V. What is its average DC output voltage?

4

A half-wave rectifier has a peak current of 24 mA. What is its average DC current?

69 Questions·
multiple choice

Sample Questions

1multiple choice
3 marks

A diode has a peak input voltage of 20 V, a barrier voltage of 0.7 V, a forward resistance of 10 Ω, and a load resistance of 500 Ω. What is the peak current through the circuit?

Show answer

37.8 mA

Use V_0 = V_B + I_0(R_F + R_L). Thus I_0 = (20 - 0.7)/(10 + 500) = 19.3/510 = 0.0378 A = 37.8 mA.

2multiple choice
3 marks

A silicon diode with barrier voltage 0.7 V is connected to a 500 Ω load and carries a peak current of 37.8 mA. What is the peak voltage across the load?

Show answer

18.9 V

The load voltage is V_L = I_0R_L = 0.0378 × 500 = 18.9 V.

3multiple choice
3 marks

A Zener diode has V_Z = 12 V and is used with a load resistance of 1 kΩ. If the Zener current is nearly zero, what input voltage is needed when the series resistance is 150 Ω?

Show answer

13.8 V

Load current is I_L = V_Z/R_L = 12/1000 = 12 mA. With I_Z ≈ 0, I = 12 mA. Then V_in = IR + V_Z = 0.012 × 150 + 12 = 1.8 + 12 = 13.8 V.

4multiple choice
3 marks

A Zener regulator has V_Z = 12 V, series resistance 150 Ω, load resistance 1 kΩ, and maximum Zener current 20 mA. What is the maximum input voltage that keeps the output at 12 V?

Show answer

16.8 V

Load current is 12 mA. At maximum Zener current, total current is I = 12 + 20 = 32 mA. Then V_in = IR + V_Z = 0.032 × 150 + 12 = 4.8 + 12 = 16.8 V.

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What are the important topics in Junction Diodes for ICSE Class 12 Physics?
Junction Diodes covers several key topics that are frequently asked in ICSE Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Junction Diodes — ICSE Class 12 Physics?
Understand the core concepts first, then work through the 69 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.

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