Tamil Nadu Board Class 12 Physics — Flashcards for Quick Revision

A: Using Coulomb's law: F = k(q₁q₂)/r² Given: - q₁ = +2 × 10⁻⁶ C - q₂ = +3 × 10⁻⁶ C - r = 1 m - k = 9 × 10⁹ N·m²/C² Step 1: F = (9 × 10⁹ × 2 × 10⁻⁶ × 3 × 10⁻⁶) / 1² Step 2: F = (9 × 10⁹ × 6 × 10⁻¹²) /

A: Coulomb's Law (Vector Form): F⃗₂₁ = (1/4πε₀) × (q₁q₂/r²) × r̂₁₂ Terms: - F⃗₂₁ = Force on charge q₂ due to q₁ - k = 1/4πε₀ = 9 × 10⁹ N·m²/C² - q₁, q₂ = Point charges in coulombs (C) - r = Distance bet

A: The electrostatic force is approximately 10³⁹ times stronger than gravitational force at atomic scales! Reason: 1. Coulomb's constant k = 9 × 10⁹ N·m²/C² is HUGE 2. Gravitational constant G = 6.67 ×

A: Law of Reflection: The angle of incidence equals the angle of reflection (i = r). Meaning: When light hits a reflecting surface, the angle at which it strikes (measured from the normal) equals the an

A: Step 1: Apply Law of Reflection Angle of reflection = Angle of incidence = 35° Step 2: Calculate angle of deviation Formula: d = 180° - (i + r) where i = angle of incidence, r = angle of reflection

A: Reason: When light from an object reflects off a plane mirror, the reflected rays appear to come from behind the mirror. Geometric explanation: 1. Two rays from object point A are drawn to mirror at

A: Electric current (I) is defined as the rate of flow of electric charge through a cross-sectional area of a conductor. It is given by I = dQ/dt. SI unit: Ampere (A). 1 Ampere = 1 Coulomb/1 second. This

A: Given: Charge (Q) = 120 C, Time (t) = 1 minute = 60 seconds. Using formula: I = Q/t. Step 1: I = 120 C / 60 s. Step 2: I = 2 C/s. Step 3: I = 2 A. Answer: The electric current is 2 amperes.

A: Conventional current flows from the positive terminal to the negative terminal of a battery (direction a positive charge would move). Electron flow is the actual movement of electrons from the negativ