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Magnetism and magnetic effects of electric current

Tamil Nadu Board · Class 12 · Physics

Flashcards for Magnetism and magnetic effects of electric current — Tamil Nadu Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

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Illustrates a current-carrying loop behaving as a magnetic dipole with North and South poles, and the direction of its magnetic moment (M) using the Right Hand Rule.
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31 Flashcards
Card 1Properties of Magnets

Define magnetic dipole moment and give its SI unit.

Answer

Magnetic dipole moment (p_m) is defined as the product of pole strength (q_m) and magnetic length (2l). Formula: p_m = q_m × 2l. SI unit: A·m² (ampere-meter squared) or J·T⁻¹ (joule per tesla). Direct

Card 2Magnetic Field due to Dipole

A bar magnet has a magnetic moment of 2.5 A·m². Calculate the magnetic field it produces at a distance of 0.2 m along its axial line.

Answer

For a short bar magnet on the axial line: B_axial = (μ₀/4π) × (2p_m/r³). Given: p_m = 2.5 A·m², r = 0.2 m, μ₀/4π = 10⁻⁷ T·m/A. Step 1: B = 10⁻⁷ × (2 × 2.5)/(0.2)³. Step 2: B = 10⁻⁷ × 5/0.008. Step 3:

Card 3Earth's Magnetic Field

Why does a magnetic compass needle always align in the north-south direction?

Answer

A compass needle is a small magnet with its own magnetic dipole moment. The Earth itself behaves like a giant bar magnet with magnetic poles near the geographic poles. When freely suspended, the compa

Card 4Earth's Magnetic Elements

Calculate the angle of dip if the horizontal component of Earth's magnetic field is 0.18 G and vertical component is 0.32 G.

Answer

The angle of dip (inclination) I is given by: tan(I) = B_V/B_H. Given: B_H = 0.18 G, B_V = 0.32 G. Step 1: tan(I) = 0.32/0.18 = 1.778. Step 2: I = tan⁻¹(1.778) = 60.5°. Step 3: Verify with resultant B

Card 5Coulomb's Law of Magnetism

State Coulomb's law of magnetism and compare it with Coulomb's law of electrostatics.

Answer

Coulomb's Law of Magnetism: F = k(q_m1 × q_m2)/r², where q_m is pole strength in A·m, k = μ₀/4π = 10⁻⁷ T·m/A. Like poles repel, unlike poles attract. Comparison with Electrostatics: Both follow invers

Card 6Coulomb's Law of Magnetism

Two magnetic poles of equal strength 40 A·m are separated by 10 cm in air. Calculate the repulsive force between them.

Answer

Using Coulomb's law of magnetism: F = (μ₀/4π) × (q_m1 × q_m2)/r². Given: q_m1 = q_m2 = 40 A·m, r = 10 cm = 0.1 m, μ₀/4π = 10⁻⁷ T·m/A. Step 1: F = 10⁻⁷ × (40 × 40)/(0.1)². Step 2: F = 10⁻⁷ × 1600/0.01.

Card 7Magnetic Field of Dipole

Why does the magnetic field on the equatorial line of a bar magnet point opposite to the dipole moment?

Answer

On the equatorial line (perpendicular bisector of a bar magnet), the magnetic field is: B_equatorial = -(μ₀/4π) × (p_m/r³). The negative sign indicates the field points opposite to the magnetic moment

Card 8Torque on Bar Magnet

Calculate the torque experienced by a bar magnet with magnetic moment 0.5 A·m² when placed in Earth's magnetic field (0.35 × 10⁻⁴ T) at an angle of 30° to the field.

Answer

Torque on a dipole in magnetic field: τ = p_m × B × sin(θ). Given: p_m = 0.5 A·m², B = 0.35 × 10⁻⁴ T, θ = 30°. Step 1: τ = 0.5 × 0.35 × 10⁻⁴ × sin(30°). Step 2: sin(30°) = 0.5. Step 3: τ = 0.5 × 0.35

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What are the important topics in Magnetism and magnetic effects of electric current for Tamil Nadu Board Class 12 Physics?
Key topics in Magnetism and magnetic effects of electric current include Complete Chapter Overview: Magnetism and Magnetic Effects of Electric Current, Chapter Overview: Magnetism and Magnetic Effects of Electric Current, Magnetism and Magnetic Effects - Comprehensive Concept Map. These are the concepts Tamil Nadu Board Class 12 examiners draw on most — study them first, then practise related questions.
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