Junction Diodes
ICSE · Class 12 · Physics
Most important questions from Junction Diodes for ICSE Class 12 Physics board exam 2026. MCQs, short answer, and long answer questions with marks.
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A diode has a peak input voltage of 20 V, a barrier voltage of 0.7 V, a forward resistance of 10 Ω, and a load resistance of 500 Ω. What is the peak current through the circuit?
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37.8 mA
Use V_0 = V_B + I_0(R_F + R_L). Thus I_0 = (20 - 0.7)/(10 + 500) = 19.3/510 = 0.0378 A = 37.8 mA.
A silicon diode with barrier voltage 0.7 V is connected to a 500 Ω load and carries a peak current of 37.8 mA. What is the peak voltage across the load?
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18.9 V
The load voltage is V_L = I_0R_L = 0.0378 × 500 = 18.9 V.
A Zener diode has V_Z = 12 V and is used with a load resistance of 1 kΩ. If the Zener current is nearly zero, what input voltage is needed when the series resistance is 150 Ω?
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13.8 V
Load current is I_L = V_Z/R_L = 12/1000 = 12 mA. With I_Z ≈ 0, I = 12 mA. Then V_in = IR + V_Z = 0.012 × 150 + 12 = 1.8 + 12 = 13.8 V.
A Zener regulator has V_Z = 12 V, series resistance 150 Ω, load resistance 1 kΩ, and maximum Zener current 20 mA. What is the maximum input voltage that keeps the output at 12 V?
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16.8 V
Load current is 12 mA. At maximum Zener current, total current is I = 12 + 20 = 32 mA. Then V_in = IR + V_Z = 0.032 × 150 + 12 = 4.8 + 12 = 16.8 V.
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