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Solution Of Right Triangles — Flashcards

ICSE · Class 9 · Mathematics

30 flashcards for Solution Of Right Triangles (ICSE Class 9 Mathematics) to test yourself on key terms and facts.

39 questions30 flashcards8 formulas & key relations5 concepts

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A labeled diagram showing a right-angled triangle with one side length and one acute angle provided. The unknown sides and angles are indicated, demonstrating how trigonometric ratios (sine, cosine, t
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30 Flashcards·
Solving a right-angled triangleTrigonometric ratio choiceFinding angles using sineFinding angles using tangentMethod for solving right trianglesFinding a side using tangentFinding an acute angle
Card 1Solving a right-angled triangle

Solve: In right-angled triangle ABC, right-angled at B, BC = 20 cm and angle A = 30°. Find AB.

Answer

Step 1: Use the ratio for base and perpendicular side relative to angle A. Step 2: AB / BC = cot 30°. Step 3: AB / 20 = √3. Step 4: AB = 20√3 cm. Step 5: AB = 20 × 1.732 = 34.64 cm. Answer: 34.64 cm…

Card 2Trigonometric ratio choice

Why is AB / BC = cot 30° in the right triangle with angle A = 30°?

Answer

Step 1: For angle A, AB is the base and BC is the perpendicular side. Step 2: The ratio base / perpendicular equals cot. Step 3: So AB / BC = cot 30°. Example: If BC = 20 cm, then AB = 20√3 cm = 34.64…

Card 3Finding angles using sine

Find x: sin x° = 5/10.

Answer

Step 1: Write the ratio as a trig form. Step 2: sin x° = Perp / Hypt = 5/10 = 1/2. Step 3: 1/2 = sin 30°. Step 4: So x = 30°. Answer: 30°…

Card 4Finding angles using tangent

Find y: tan y° = 10/10.

Answer

Step 1: Write the ratio as a trig form. Step 2: tan y° = Perp / Base = 10/10 = 1. Step 3: 1 = tan 45°. Step 4: So y = 45°. Answer: 45°…

Card 5Method for solving right triangles

When one side and one acute angle are given, how is the unknown side found?

Answer

Step 1: Identify the given angle and the known side. Step 2: Choose the trig ratio that connects the unknown side and known side. Step 3: Use the form unknown side / known side = corresponding trigono…

Card 6Finding a side using tangent

Solve: In right triangle ABD, tan 45° = AD / BD and AD = 10 cm. Find BD.

Answer

Step 1: Use tan 45° = AD / BD. Step 2: tan 45° = 1. Step 3: 1 = 10 / BD. Step 4: BD = 10 cm. Answer: 10 cm…

Card 7Finding an acute angle

In triangle ADC, sin θ = AD / AC = 10 / 20. Find θ.

Answer

Step 1: Write the sine ratio. Step 2: sin θ = 10/20 = 1/2. Step 3: 1/2 = sin 30°. Step 4: So θ = 30°. Answer: 30°…

Card 8Finding a side using tangent

In triangle ADC, tan θ = AD / DC and θ = 30°. If AD = 10 cm, find DC.

Answer

Step 1: Use tan θ = AD / DC. Step 2: tan 30° = 1/√3. Step 3: 1/√3 = 10 / DC. Step 4: DC = 10√3 cm. Step 5: DC = 10 × 1.732 = 17.32 cm. Answer: 17.32 cm…

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Frequently Asked Questions

What are the important topics in Solution Of Right Triangles for ICSE Class 9 Mathematics?
Key topics in Solution Of Right Triangles include Meaning of solving a right-angled triangle, Finding missing angles using trigonometric ratios, Two right triangles sharing a side, Two-triangle method with unknown length AC. Study these first, then practise questions on each for Class 9 exams.
How many flashcards are available for Solution Of Right Triangles?
There are 30 flashcards for Solution Of Right Triangles covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Solution Of Right Triangles for Class 9 exams?
Learn the core ideas first, then work through the 39 practice questions on Solution Of Right Triangles. Revise definitions regularly and use flashcards for quick recall before the exam.

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