Solution Of Right Triangles
ICSE · Class 9 · Mathematics
Flashcards for Solution Of Right Triangles — ICSE Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
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See them allSolve: In right-angled triangle ABC, right-angled at B, BC = 20 cm and angle A = 30°. Find AB.
Answer
Step 1: Use the ratio for base and perpendicular side relative to angle A. Step 2: AB / BC = cot 30°. Step 3: AB / 20 = √3. Step 4: AB = 20√3 cm. Step 5: AB = 20 × 1.732 = 34.64 cm. Answer: 34.64 cm…
Why is AB / BC = cot 30° in the right triangle with angle A = 30°?
Answer
Step 1: For angle A, AB is the base and BC is the perpendicular side. Step 2: The ratio base / perpendicular equals cot. Step 3: So AB / BC = cot 30°. Example: If BC = 20 cm, then AB = 20√3 cm = 34.64…
Find x: sin x° = 5/10.
Answer
Step 1: Write the ratio as a trig form. Step 2: sin x° = Perp / Hypt = 5/10 = 1/2. Step 3: 1/2 = sin 30°. Step 4: So x = 30°. Answer: 30°…
Find y: tan y° = 10/10.
Answer
Step 1: Write the ratio as a trig form. Step 2: tan y° = Perp / Base = 10/10 = 1. Step 3: 1 = tan 45°. Step 4: So y = 45°. Answer: 45°…
When one side and one acute angle are given, how is the unknown side found?
Answer
Step 1: Identify the given angle and the known side. Step 2: Choose the trig ratio that connects the unknown side and known side. Step 3: Use the form unknown side / known side = corresponding trigono…
Solve: In right triangle ABD, tan 45° = AD / BD and AD = 10 cm. Find BD.
Answer
Step 1: Use tan 45° = AD / BD. Step 2: tan 45° = 1. Step 3: 1 = 10 / BD. Step 4: BD = 10 cm. Answer: 10 cm…
In triangle ADC, sin θ = AD / AC = 10 / 20. Find θ.
Answer
Step 1: Write the sine ratio. Step 2: sin θ = 10/20 = 1/2. Step 3: 1/2 = sin 30°. Step 4: So θ = 30°. Answer: 30°…
In triangle ADC, tan θ = AD / DC and θ = 30°. If AD = 10 cm, find DC.
Answer
Step 1: Use tan θ = AD / DC. Step 2: tan 30° = 1/√3. Step 3: 1/√3 = 10 / DC. Step 4: DC = 10√3 cm. Step 5: DC = 10 × 1.732 = 17.32 cm. Answer: 17.32 cm…
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