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Area and Perimeter of Plane Figures

ICSE · Class 9 · Mathematics

Flashcards for Area and Perimeter of Plane Figures — ICSE Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions31 flashcards5 concepts

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A visual comparison defining perimeter as the length of the boundary and area as the measure of the surface enclosed by the boundary, using simple geometric shapes like a square and a rectangle.
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31 Flashcards
Card 1Triangle perimeter

Find the perimeter of a triangle with sides 8 cm, 10 cm, and 12 cm.

Answer

Step 1: Add all side lengths. Perimeter = 8 + 10 + 12 Step 2: Calculate. Perimeter = 30 cm Answer: 30 cm

Card 2Triangle area

Find the area of a triangle with base 10 cm and height 6 cm.

Answer

Use Area = 1/2 × base × corresponding height. Step 1: Substitute values. Area = 1/2 × 10 × 6 Step 2: Multiply. Area = 30 cm² Answer: 30 cm²

Card 3Triangle base and height

Why can any side of a triangle be taken as the base?

Answer

Any side can be chosen as the base because the area formula depends on a matching height drawn perpendicular to that side. Example: If AC is the base, BE is the corresponding height. If AB is the base

Card 4Heron's formula

Find the area of a triangle with sides 17 cm, 8 cm, and 15 cm using Heron's formula.

Answer

Step 1: Find semi-perimeter. s = (17 + 8 + 15)/2 = 20 cm Step 2: Apply Heron's formula. Area = √[s(s-a)(s-b)(s-c)] Area = √[20(20-17)(20-8)(20-15)] Step 3: Simplify. Area = √[20 × 3 × 12 × 5] = √3600

Card 5Heron's formula

Formula for Heron's formula and semi-perimeter.

Answer

Heron's formula: Area = √[s(s-a)(s-b)(s-c)] where s = (a + b + c)/2 a, b, c are the sides of the triangle. Quick example: For sides 5 cm, 5 cm, 6 cm, s = 8 cm and Area = √[8(3)(3)(2)] = 12 cm².

Card 6Right-angled triangle area

The sides of a right-angled triangle containing the right angle are 5 cm and 12 cm. Find its area.

Answer

Use Area = 1/2 × AB × BC. Step 1: Substitute the two perpendicular sides. Area = 1/2 × 5 × 12 Step 2: Multiply. Area = 30 cm² Answer: 30 cm²

Card 7Right-angled triangle equation

Solve: The sides containing the right angle of a triangle are 5x cm and (3x - 1) cm. If the area is 60 cm², find the sides.

Answer

Step 1: Use the area formula. 60 = 1/2 × 5x × (3x - 1) Step 2: Multiply both sides by 2. 120 = 15x² - 5x Step 3: Rearrange. 3x² - x - 24 = 0 Step 4: Solve the quadratic. x = 3 or x = -8/3 Step 5: Reje

Card 8Equilateral triangle

Find the perimeter and area of an equilateral triangle with side 14 cm.

Answer

Step 1: Use the perimeter formula. Perimeter = 3a = 3 × 14 = 42 cm Step 2: Use the area formula. Area = (√3/4)a² Area = (√3/4) × 14² Area = (√3/4) × 196 Area = 49√3 cm² Approximate area ≈ 84.87 cm² An

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Frequently Asked Questions

What are the important topics in Area and Perimeter of Plane Figures for ICSE Class 9 Mathematics?
Area and Perimeter of Plane Figures covers several key topics that are frequently asked in ICSE Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Area and Perimeter of Plane Figures — ICSE Class 9 Mathematics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Area and Perimeter of Plane Figures?
There are 31 flashcards for Area and Perimeter of Plane Figures covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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