Skip to main content
Chapter 11 of 14
Flashcards

Electric Current Through Conductors

Maharashtra Board · Class 11 · Physics

Flashcards for Electric Current Through Conductors — Maharashtra Board Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions24 flashcards5 concepts

Interactive on Super Tutor

Studying Electric Current Through Conductors? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.

1,000+ Class 11 students started this chapter today

24 Flashcards
Card 1Electric Current

What is electric current and what is its SI unit?

Answer

Electric current is defined as the amount of charge flowing through a cross-section per unit time. I = q/t. The SI unit is ampere (A). 1 ampere = 1 coulomb/second. Current can range from nanoamperes (

Card 2Electric Current

What is the sign convention for electric current direction?

Answer

By convention, the direction of current is taken as the direction in which positive charges would move, even though in metallic conductors, it is actually electrons (negative charges) that move in the

Card 3Drift Velocity

Define drift velocity and derive its relation with current.

Answer

Drift velocity (Vd) is the average velocity with which free electrons move in a conductor under the influence of an electric field. Derivation: For a conductor with length L, cross-sectional area A, a

Card 4Drift Velocity

A metallic wire of diameter 0.02m has 10²⁸ free electrons per m³. Find drift velocity for current of 100A. (e = 1.6 × 10⁻¹⁹ C)

Answer

Given: D = 0.02m, r = 0.01m, n = 10²⁸ electrons/m³, I = 100A, e = 1.6 × 10⁻¹⁹ C Solution: A = πr² = 3.142 × (0.01)² = 3.142 × 10⁻⁴ m² Vd = I/(nAe) = 100/(3.142 × 10⁻⁴ × 10²⁸ × 1.6 × 10⁻¹⁹) = 100/(5.02

Card 5Ohm's Law

State Ohm's law and write its mathematical expression.

Answer

Ohm's law states: 'The current through a conductor is directly proportional to the potential difference applied across its ends, provided the physical state of the conductor remains unchanged.' Mathem

Card 6Resistance and Conductance

What is resistance and conductance? Give their units.

Answer

Resistance (R) is the opposition offered by a conductor to the flow of current. R = V/I. Unit: ohm (Ω). 1Ω = 1V/1A. Conductance (C) is the reciprocal of resistance. C = 1/R. Unit: siemens (S) or (Ω)⁻¹

Card 7Ohm's Law

A flashlight uses two 1.5V batteries to provide 0.5A current. Find the resistance of the filament.

Answer

Given: Total voltage V = 2 × 1.5V = 3.0V, Current I = 0.5A Solution: Using Ohm's law, R = V/I = 3.0V/0.5A = 6.0Ω Therefore, resistance of the glowing filament = 6.0Ω

Card 8Resistivity

Derive the microscopic form of Ohm's law and explain resistivity.

Answer

For an electron in electric field E: Force F = eE, acceleration a = eE/m. If τ is average time between collisions, drift velocity Vd = aτ = (eEτ/m). From Vd = J/(ne), we get J/(ne) = (eEτ/m), which gi

+16 more flashcards available

Practice All

Frequently Asked Questions

What are the important topics in Electric Current Through Conductors for Maharashtra Board Class 11 Physics?
Electric Current Through Conductors covers several key topics that are frequently asked in Maharashtra Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Electric Current Through Conductors — Maharashtra Board Class 11 Physics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Electric Current Through Conductors?
There are 24 flashcards for Electric Current Through Conductors covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Electric Current Through Conductors chapter — for free.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for Maharashtra Board Class 11 Physics.