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Thermal Properties of Matter

Maharashtra Board · Class 11 · Physics

Flashcards for Thermal Properties of Matter — Maharashtra Board Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions20 flashcards5 concepts

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20 Flashcards
Card 1Temperature and Heat

What is the fundamental difference between temperature and heat?

Answer

Temperature is a measure of the average kinetic energy of particles in a substance and determines the degree of hotness. Heat is energy in transit that flows from a body at higher temperature to one a

Card 2Temperature Scales

Convert 27°C to Fahrenheit and Kelvin scales.

Answer

Given: T_C = 27°C For Fahrenheit: T_F = (9/5)T_C + 32 = (9/5) × 27 + 32 = 48.6 + 32 = 80.6°F For Kelvin: T_K = T_C + 273.15 = 27 + 273.15 = 300.15 K Answer: 80.6°F and 300.15 K

Card 3Temperature Measurement

State the Zeroth Law of Thermodynamics and its significance in thermometry.

Answer

Zeroth Law: If systems A and B are separately in thermal equilibrium with system C, then A and B are also in thermal equilibrium with each other. Significance: This law makes temperature measurement

Card 4Absolute Temperature

What is absolute zero and why is it significant?

Answer

Absolute zero is the theoretical temperature at which all molecular motion would cease, equal to -273.15°C or 0 K. It is significant because: 1. It represents the lowest possible temperature 2. At thi

Card 5Ideal Gas Equation

Write the ideal gas equation and explain each term.

Answer

Ideal Gas Equation: PV = nRT Where: P = Pressure of gas (Pa or N/m²) V = Volume of gas (m³) n = Number of moles of gas R = Universal gas constant = 8.31 J K⁻¹ mol⁻¹ T = Absolute temperature (K) This

Card 6Linear Expansion

Define coefficient of linear expansion and derive its formula.

Answer

Definition: Coefficient of linear expansion (α) is the increase in length per unit original length at 0°C for one degree rise in temperature. Derivation: Δl/l ∝ ΔT Δl = αlΔT l_T = l₀(1 + αΔT) Where

Card 7Linear Expansion

A steel rod of length 2 m at 20°C is heated to 120°C. Find the increase in length. (α for steel = 1.3 × 10⁻⁵ K⁻¹)

Answer

Given: l₀ = 2 m T₁ = 20°C, T₂ = 120°C α = 1.3 × 10⁻⁵ K⁻¹ Formula: Δl = αl₀ΔT ΔT = T₂ - T₁ = 120 - 20 = 100°C Δl = 1.3 × 10⁻⁵ × 2 × 100 Δl = 2.6 × 10⁻³ m = 2.6 mm The rod increases by 2.6 mm in len

Card 8Thermal Expansion

Establish the relationship between coefficients of linear (α), areal (β), and volume (γ) expansion.

Answer

Derivation: For a cube of side l₀: - Linear: l = l₀(1 + αT) - Area: A = l² = l₀²(1 + αT)² ≈ l₀²(1 + 2αT) So β = 2α - Volume: V = l³ = l₀³(1 + αT)³ ≈ l₀³(1 + 3αT) So γ = 3α Relationship: α : β : γ

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Thermal Properties of Matter covers several key topics that are frequently asked in Maharashtra Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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