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Spontaneity Of Chemical Reactions

NIOS · Class 12 · Chemistry

Flashcards for Spontaneity Of Chemical Reactions — NIOS Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

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Card 1Spontaneous and Non-Spontaneous Processes

Define a spontaneous process and give one example.

Answer

A spontaneous process is a process that occurs in a system by itself without requiring continuous external action. Once started, it continues naturally. Example: Cooling of hot water at room temperatu

Card 2Spontaneous and Non-Spontaneous Processes

What is the relationship between a spontaneous process and its reverse?

Answer

If a process is spontaneous in one direction, its reverse process is non-spontaneous in that direction. For example, rusting of iron (4Fe + 3O₂ → 2Fe₂O₃) is spontaneous, but the reduction of Fe₂O₃ bac

Card 3Entropy

Define entropy and explain what it measures.

Answer

Entropy (S) is a thermodynamic property that measures the degree of disorder or randomness in a system. Higher entropy means greater disorder. For states of matter: Solid < Liquid < Gas (in terms of e

Card 4Entropy

Write the mathematical expression for entropy change during a reversible process.

Answer

ΔS = q_rev / T, where ΔS is the change in entropy, q_rev is the heat supplied reversibly at constant temperature, and T is the absolute temperature in Kelvin. This equation shows that entropy change d

Card 5Entropy

Explain why entropy increases when gases mix spontaneously.

Answer

When two ideal gases mix spontaneously (as when bulb I and bulb II are connected), the particles spread out to occupy a larger volume, increasing disorder. The internal energy (ΔU) and enthalpy (ΔH) d

Card 6Second Law of Thermodynamics

What is the Second Law of Thermodynamics?

Answer

The Second Law of Thermodynamics states that all spontaneous or natural processes produce an increase in the entropy of the universe. Mathematically: ΔS_universe = ΔS_system + ΔS_surroundings > 0 for

Card 7Entropy Change in Phase Transitions

Calculate the entropy change for the vaporization of water at 373K, given Δ_vap H = 40.8 kJ mol⁻¹.

Answer

Formula: Δ_vap S = Δ_vap H / T. Step 1: Convert enthalpy to J mol⁻¹: 40.8 kJ mol⁻¹ = 40,800 J mol⁻¹. Step 2: Substitute values: Δ_vap S = 40,800 J mol⁻¹ / 373 K = 109.4 J K⁻¹ mol⁻¹. Answer: 109.4 J K⁻

Card 8Entropy Change in Phase Transitions

Calculate the entropy change for melting of ice at 273K, given Δ_fus H = 6.02 kJ mol⁻¹.

Answer

Formula: Δ_fus S = Δ_fus H / T. Step 1: Convert to J mol⁻¹: 6.02 kJ mol⁻¹ = 6,020 J mol⁻¹. Step 2: Substitute: Δ_fus S = 6,020 J mol⁻¹ / 273 K = 22.05 J K⁻¹ mol⁻¹. Answer: 22.05 J K⁻¹ mol⁻¹ (approxima

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