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Thermodynamics

Punjab Board · Class 11 · Chemistry

Flashcards for Thermodynamics — Punjab Board Class 11 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions25 flashcards5 concepts

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A diagram illustrating the three types of thermodynamic systems: open, closed, and isolated, showing the exchange of matter and energy with the surroundings.
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25 Flashcards
Card 1System Classification

Define a thermodynamic system and distinguish between open, closed, and isolated systems with one example each.

Answer

System: The part of universe where observations are made. Surroundings: Everything else. Open System: Exchange of both matter and energy. Example: Reactants in an open beaker. Closed System: Exchang

Card 2Internal Energy

What is internal energy (U)? Why is it a state function?

Answer

Internal Energy (U): Sum of all forms of energy in a system (chemical, mechanical, electrical, etc.). State Function Property: The change in internal energy (ΔU) depends ONLY on initial and final sta

Card 3Pressure-Volume Work

Calculate work done when 2 liters of ideal gas at 10 atm pressure expands to 10 liters against external pressure of 1 atm.

Answer

Given: V_initial = 2 L, V_final = 10 L, p_external = 1 atm Formula: w = -p_ext × ΔV Step 1: ΔV = V_final - V_initial = 10 - 2 = 8 L Step 2: w = -1 atm × 8 L = -8 L·atm Step 3: Convert to joules: w

Card 4First Law of Thermodynamics

State the First Law of Thermodynamics and explain its significance.

Answer

First Law Statement: 'Energy of an isolated system is constant' or 'Energy cannot be created or destroyed, only converted.' Mathematical Form: ΔU = q + w Where: - ΔU = change in internal energy - q

Card 5Enthalpy

What is enthalpy (H)? How does it relate to internal energy?

Answer

Enthalpy (H): Defined as H = U + pV Where: U = internal energy, p = pressure, V = volume Change in Enthalpy: ΔH = ΔU + Δ(pV) At constant pressure: ΔH = ΔU + pΔV Key Relationship: ΔH = ΔU + Δn_g RT

Card 6Enthalpy and Internal Energy Relationship

Calculate internal energy change (ΔU) for vaporization of 1 mole of water at 100°C and 1 bar, given ΔH_vap = 41.00 kJ/mol.

Answer

Given: ΔH_vap = 41.00 kJ/mol, T = 373 K, 1 mole water Formula: ΔU = ΔH - Δn_g RT Step 1: Identify Δn_g H₂O(l) → H₂O(g) Δn_g = 1 (product) - 0 (reactant) = 1 mole Step 2: Calculate Δn_g RT Δn_g RT =

Card 7Properties Classification

What is the difference between extensive and intensive properties? Give three examples of each.

Answer

Extensive Properties: Depend on the quantity or size of matter present Examples: 1. Mass - increases when amount of substance increases 2. Volume - larger sample has larger volume 3. Internal energy (

Card 8Heat Capacity

Define heat capacity and molar heat capacity. Calculate heat required to raise temperature of 50g water by 10°C (specific heat of water = 4.18 J/g°C).

Answer

Heat Capacity (C): Amount of heat required to raise temperature of substance by 1°C (or 1 K) Formula: q = C × ΔT Molar Heat Capacity (C_m): Heat capacity per mole of substance Formula: C_m = C/n Spe

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Frequently Asked Questions

What are the important topics in Thermodynamics for Punjab Board Class 11 Chemistry?
Key topics in Thermodynamics include Thermodynamics - Complete Chapter Overview, Thermodynamics — Complete Chapter Overview, Thermodynamics Concepts Overview. These are the concepts Punjab Board Class 11 examiners draw on most — study them first, then practise related questions.
How to score full marks in Thermodynamics — Punjab Board Class 11 Chemistry?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Thermodynamics?
There are 25 flashcards for Thermodynamics covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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