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Current Electricity

Punjab Board · Class 12 · Physics

Flashcards for Current Electricity — Punjab Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions30 flashcards5 concepts

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A standard circuit diagram of a Wheatstone bridge, showing four resistors, a galvanometer, and a battery, highlighting the balanced condition.
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30 Flashcards
Card 1Electric Current

Define electric current and state its SI unit.

Answer

Electric current (I) is defined as the amount of charge flowing through a cross-section of a conductor per unit time. Mathematically: I = Q/t, where Q is charge in coulombs and t is time in seconds. S

Card 2Drift Velocity

A copper wire has 8.5 × 10²⁸ free electrons per m³. If a current of 2.0 A flows through a cross-sectional area of 2.0 × 10⁻⁷ m², calculate the drift velocity of electrons.

Answer

Given: n = 8.5 × 10²⁸ m⁻³, I = 2.0 A, A = 2.0 × 10⁻⁷ m², e = 1.6 × 10⁻¹⁹ C Formula: I = neAv_d, so v_d = I/(neA) Step 1: Calculate denominator = 8.5 × 10²⁸ × 1.6 × 10⁻¹⁹ × 2.0 × 10⁻⁷ = 8.5 × 1.6 × 2.0

Card 3Ohm's Law

State Ohm's Law and explain what happens when voltage across a conductor doubles.

Answer

Ohm's Law: V = IR, where V is potential difference in volts, I is current in amperes, and R is resistance in ohms. This states that current is directly proportional to voltage if resistance remains co

Card 4Temperature Dependence of Resistivity

A nichrome wire has a resistance of 80 Ω at 27°C. The temperature coefficient of resistance is 0.0004 °C⁻¹. Calculate its resistance at 227°C.

Answer

Given: R₀ = 80 Ω at T₀ = 27°C, α = 0.0004 °C⁻¹, T = 227°C Formula: R_T = R₀[1 + α(T - T₀)] Step 1: Calculate temperature change: ΔT = T - T₀ = 227 - 27 = 200°C Step 2: Calculate α(ΔT) = 0.0004 × 200 =

Card 5Resistivity and Resistance

Derive the relationship between resistance (R), resistivity (ρ), length (l), and cross-sectional area (A).

Answer

Starting from: Resistance is proportional to length (R ∝ l) and inversely proportional to area (R ∝ 1/A). Combining: R ∝ l/A Introducing proportionality constant ρ (resistivity): R = ρl/A Where: R = r

Card 6Drift Velocity and Collision

Why do electrons move with constant drift velocity instead of continuously accelerating under the electric field?

Answer

In a conductor, free electrons experience electric force (F = -eE) and accelerate initially. However, they constantly collide with positive ions in the lattice at random intervals. After each collisio

Card 7Electrical Power

Calculate the power dissipated in a 5 Ω resistor when 3 A of current flows through it.

Answer

Given: R = 5 Ω, I = 3 A Formula: P = I²R Step 1: P = (3)² × 5 = 9 × 5 = 45 W Alternative formula check: V = IR = 3 × 5 = 15 V Using P = V²/R = (15)²/5 = 225/5 = 45 W ✓ Using P = VI = 15 × 3 = 45 W ✓ A

Card 8Series and Parallel Combinations

Two identical resistors are connected in series. If the equivalent resistance is 100 Ω, what is the resistance of each resistor?

Answer

Given: Two identical resistors in series, R_eq = 100 Ω, R₁ = R₂ = R (unknown) Formula for series: R_eq = R₁ + R₂ Step 1: Since resistors are identical: R_eq = R + R = 2R Step 2: 100 = 2R Step 3: R = 1

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Frequently Asked Questions

What are the important topics in Current Electricity for Punjab Board Class 12 Physics?
Key topics in Current Electricity include Flowchart showing how current is defined from charge flow, the formula, units, and practical examples, Flowchart illustrating the free electron model in conductors with and without electric field, Flowchart showing Ohm's law and its three forms for calculating V, I, or R. These are the concepts Punjab Board Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Current Electricity — Punjab Board Class 12 Physics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Current Electricity?
There are 30 flashcards for Current Electricity covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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