Electric Charges and Fields

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Step 1: When spheres touch, charge distributes equally. Total charge = +10 + 20 = +30 μC Each sphere gets = 30/2 = +15 μC Step 2: After separation, both have +15 μC r = 5 cm = 0.05 m Step 3: Apply C…

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When you pull off a woolen sweater, friction occurs between the wool and synthetic cloth. This friction causes electrons to transfer from one material to another, creating a charge separation. The ch…

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Coulomb's Law (Vector Form): 𝐅₂₁ = (1/4πε₀) × (q₁q₂/r₂₁²) × 𝐫̂₂₁ Where: - 𝐅₂₁ = Force on charge q₂ due to charge q₁ (in Newtons) - q₁, q₂ = Point charges (in Coulombs) - r₂₁ = Distance between charg…

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Step 1: Setup - Place charges: - q₁ = +2 μC at vertex A - q₂ = +3 μC at vertex B (test charge) - q₃ = -2 μC at vertex C - Side length = 10 cm = 0.1 m Step 2: Force on q₂ due to q₁ (repulsive, along A…

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The electric field concept is significant for several reasons: 1. **Independence from Test Charge**: The electric field E = F/q is independent of the test charge placed at a point. It represents a pr…

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Step 1: Find the force on electron Charge on electron: q = -e = -1.6 × 10⁻¹⁹ C Electric field: E = 2000 N/C (in +x direction) Force: F = qE = (-1.6 × 10⁻¹⁹) × (2000) F = -3.2 × 10⁻¹⁶ N (in -x directi…

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Explanation using Coulomb's Law: Consider a point P inside the shell. Divide the shell into small area elements. Each element dA produces a field at P. Consider two elements on opposite sides of a lin…

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Given: Linear charge density: λ = 5 μC/m = 5 × 10⁻⁶ C/m Perpendicular distance: r = 2 cm = 0.02 m k = 9 × 10⁹ N·m²/C² For an infinitely long charged wire, using Gauss's Law: Step 1: Apply Gauss's La…