Moving Charges and Magnetic Field
ICSE · Class 12 · Physics
Flashcards for Moving Charges and Magnetic Field — ICSE Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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Get startedState the concept of magnetic field and the direction of magnetic field near a magnet.
Answer
A magnetic field is the region near a magnet where a magnetic needle experiences a torque and rests in a definite direction. The direction of the field at a point is the direction from the south pole …
Why does a magnetic needle near a current-carrying wire deflect when current flows?
Answer
A current-carrying wire produces a magnetic field around it. A magnetic needle placed near the wire experiences a torque due to this field and turns from its original direction. Reversing the current …
A wire carrying 50 A current is kept 2.5 m away from a point. Find the magnetic field at that point due to the long straight wire.
Answer
Given: I = 50 A, r = 2.5 m Formula: B = (μ0)/(2π) · I/r Step 1: Substitute values B = (2 × 10^-7) × (50)/(2.5) T Step 2: Calculate B = 4 × 10^-6 T Answer: 4 × 10^-6 tesla…
State Biot-Savart law in scalar form.
Answer
dB = (μ0/4π) · (I dl sinθ)/r^2 Here, dB is the field due to a small current element Idl, I is current, dl is element length, θ is the angle between dl and r, and r is the distance from the element to …
Why is Biot-Savart law called the magnetic equivalent of Coulomb’s law?
Answer
Both laws are inverse-square laws and describe fields produced by a source element. Coulomb’s law gives electric field due to charge, while Biot-Savart law gives magnetic field due to current element.
A current of 1.0 A flows in a circular coil of radius 0.08 m having 100 turns. Find the magnetic field at the centre.
Answer
Given: N = 100, I = 1.0 A, a = 0.08 m Formula: B = μ0NI/(2a) Step 1: Substitute values B = (4π × 10^-7) × 100 × 1.0 / (2 × 0.08) T Step 2: Calculate B = 7.85 × 10^-4 T approximately Answer: 7.85 × 10^…
A current of 9 A flows in a circular arc of radius 0.10 m subtending 60° at the centre. Find the magnetic field at the centre.
Answer
Given: I = 9 A, a = 0.10 m, θ = 60° = π/3 rad Formula: B_arc = (μ0/4π)(I/a)θ Step 1: Substitute values B = (10^-7) × (9/0.10) × (π/3) T Step 2: Calculate B = 9.42 × 10^-6 T Answer: 9.42 × 10^-6 tesla…
A long straight conductor carries 10 A. Find the magnetic field at 0.20 m from it.
Answer
Given: I = 10 A, r = 0.20 m Formula: B = μ0I/(2πr) Step 1: Substitute values B = (2 × 10^-7) × (10)/(0.20) T Step 2: Calculate B = 1 × 10^-5 T Answer: 1 × 10^-5 tesla…
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