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Chapter 10 of 16
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States of Matter

Maharashtra Board · Class 11 · Chemistry

Flashcards for States of Matter — Maharashtra Board Class 11 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards5 concepts

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20 Flashcards
Card 1Introduction to States of Matter

What are the three main states of matter and how are they interconvertible?

Answer

The three main states of matter are: 1. Solid - particles tightly held in regular arrangement 2. Liquid - particles loosely packed with irregular arrangement 3. Gas - particles widely separated in hig

Card 2Intermolecular Forces

Define intermolecular forces and explain their role in determining states of matter.

Answer

Intermolecular forces are attractive and repulsive forces present between neighboring molecules. They decrease with increasing distance. Role in states: • Strong intermolecular forces → Solids • Mode

Card 3Types of Intermolecular Forces

What are the five types of intermolecular forces? List them in order of strength.

Answer

The five types of intermolecular forces are: 1. Ion-dipole interactions (strongest, 10-50 kJ/mol) 2. Hydrogen bonding (moderate, 10-40 kJ/mol) 3. Dipole-dipole interactions (weak, 3-4 kJ/mol) 4. Dipo

Card 4Dipole-Dipole Interactions

Define dipole moment and explain dipole-dipole interactions with an example.

Answer

Dipole moment (μ) is the product of magnitude of charge (Q) and distance between centers of positive and negative charge (r). μ = Q × r, Unit: Debye (D) Dipole-dipole interactions occur between polar

Card 5Hydrogen Bonding

Explain hydrogen bonding with examples and its effect on boiling point.

Answer

Hydrogen bonding is a special dipole-dipole attraction when hydrogen is bonded to highly electronegative atoms (N, O, F). Definition: Electrostatic attraction between H^δ+ of one molecule and electro

Card 6Boyle's Law

State Boyle's Law and write its mathematical expression with graphical representation.

Answer

Boyle's Law: For a fixed mass of gas at constant temperature, pressure is inversely proportional to volume. Mathematical Expression: P ∝ 1/V (at constant T, n) P = k₁/V PV = k₁ (constant) P₁V₁ = P₂V₂

Card 7Boyle's Law Calculations

A gas occupies 25 mL at 1 atm pressure. Calculate its volume when pressure is increased to 1.25 atm at constant temperature.

Answer

Given: P₁ = 1 atm, V₁ = 25 mL P₂ = 1.25 atm, V₂ = ? Using Boyle's Law: P₁V₁ = P₂V₂ V₂ = P₁V₁/P₂ V₂ = (1 × 25)/1.25 V₂ = 20 mL Answer: The gas will occupy 20 mL at 1.25 atm pressure. Note: Volume d

Card 8Charles' Law

State Charles' Law and explain absolute zero temperature.

Answer

Charles' Law: At constant pressure, volume of a fixed mass of gas is directly proportional to absolute temperature. Mathematical Expression: V ∝ T (at constant P, n) V = k₂T V/T = constant V₁/T₁ = V₂

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