Dual Nature of Radiation and Matter
Madhya Pradesh Board · Class 12 · Physics
Flashcards for Dual Nature of Radiation and Matter — Madhya Pradesh Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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Get startedआवृत्ति 6.0 × 10^14 Hz वाला एक प्रकाश स्रोत विकिरण उत्सर्जित करता है। एक फोटॉन की ऊर्जा क्या है?
Answer
दिया गया: आवृत्ति ν = 6.0 × 10^14 Hz, प्लांक नियतांक h = 6.626 × 10^-34 J s सूत्र: E = hν चरण 1: E = (6.626 × 10^-34 J s)(6.0 × 10^14 s^-1) चरण 2: E = 3.976 × 10^-19 J उत्तर: प्रति फोटॉन 3.98 × 10^-19…
A light source of frequency 6.0 × 10^14 Hz emits radiation. What is the energy of one photon?
Answer
Given: frequency ν = 6.0 × 10^14 Hz, Planck's constant h = 6.626 × 10^-34 J s Formula: E = hν Step 1: E = (6.626 × 10^-34 J s)(6.0 × 10^14 s^-1) Step 2: E = 3.976 × 10^-19 J Answer: 3.98 × 10^-19 J pe…
A laser emits light of power 2.0 × 10^-3 W at frequency 6.0 × 10^14 Hz. How many photons are emitted per second on average?
Answer
Given: Power P = 2.0 × 10^-3 W, frequency ν = 6.0 × 10^14 Hz, h = 6.626 × 10^-34 J s Step 1: Energy of one photon, E = hν = (6.626 × 10^-34)(6.0 × 10^14) = 3.976 × 10^-19 J Step 2: Number of photons p…
2.0 × 10^-3 W शक्ति वाला एक लेज़र 6.0 × 10^14 Hz आवृत्ति पर प्रकाश उत्सर्जित करता है। औसतन प्रति सेकंड कितने फोटॉन उत्सर्जित होते हैं?
Answer
दिया गया: शक्ति P = 2.0 × 10^-3 W, आवृत्ति ν = 6.0 × 10^14 Hz, h = 6.626 × 10^-34 J s चरण 1: एक फोटॉन की ऊर्जा, E = hν = (6.626 × 10^-34)(6.0 × 10^14) = 3.976 × 10^-19 J चरण 2: प्रति सेकंड फोटॉनों की …
एक फोटॉन की आवृत्ति 5.0 × 10^14 Hz है। इसका संवेग ज्ञात कीजिए।
Answer
दिया गया: ν = 5.0 × 10^14 Hz, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s सूत्र: p = hν/c चरण 1: p = (6.626 × 10^-34 × 5.0 × 10^14) / (3.0 × 10^8) चरण 2: p = 3.313 × 10^-19 / 3.0 × 10^8 चरण 3: p = 1.10…
A photon has frequency 5.0 × 10^14 Hz. Find its momentum.
Answer
Given: ν = 5.0 × 10^14 Hz, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s Formula: p = hν/c Step 1: p = (6.626 × 10^-34 × 5.0 × 10^14) / (3.0 × 10^8) Step 2: p = 3.313 × 10^-19 / 3.0 × 10^8 Step 3: p = 1.
A photon has wavelength 500 nm. Find its energy.
Answer
Given: λ = 500 nm = 500 × 10^-9 m, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s Formula: E = hc/λ Step 1: E = (6.626 × 10^-34 × 3.0 × 10^8) / (500 × 10^-9) Step 2: E = 1.9878 × 10^-25 / 5.00 × 10^-7 Ste…
एक फोटॉन की तरंगदैर्घ्य 500 nm है। इसकी ऊर्जा ज्ञात कीजिए।
Answer
दिया गया: λ = 500 nm = 500 × 10^-9 m, h = 6.626 × 10^-34 J s, c = 3.0 × 10^8 m/s सूत्र: E = hc/λ चरण 1: E = (6.626 × 10^-34 × 3.0 × 10^8) / (500 × 10^-9) चरण 2: E = 1.9878 × 10^-25 / 5.00 × 10^-7 चरण …
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