Wave Optics
Madhya Pradesh Board · Class 12 · Physics
Flashcards for Wave Optics — Madhya Pradesh Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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Explore the full setState Descartes’ corpuscular model of light and its key prediction about refraction.
Answer
Descartes gave the corpuscular model of light in 1637 and derived Snell’s law. The model predicts that when light bends towards the normal in a denser medium, its speed becomes greater in the second m…
प्रकाश का Descartes’ कणिका मॉडल और अपवर्तन के बारे में इसकी मुख्य भविष्यवाणी बताइए।
Answer
Descartes ने 1637 में प्रकाश का कणिका मॉडल दिया और Snell’s law व्युत्पन्न किया। यह मॉडल भविष्यवाणी करता है कि जब प्रकाश सघन माध्यम में अभिलम्ब की ओर मुड़ता है, तो उसकी चाल दूसरे माध्यम में अधिक हो जात…
कणिका मॉडल की तुलना में प्रकाश का तरंग सिद्धांत क्यों स्वीकार किया गया?
Answer
Thomas Young के 1801 के व्यतिकरण प्रयोग ने स्थापित किया कि प्रकाश तरंग व्यवहार दिखाता है। बाद में, Foucault के 1850 के प्रयोग ने यह पुष्टि की कि पानी में प्रकाश की चाल हवा की तुलना में कम होती है, जो …
Why was the wave theory of light accepted over the corpuscular model?
Answer
Thomas Young’s interference experiment in 1801 established that light shows wave behaviour. Later, Foucault’s 1850 experiment confirmed that speed of light in water is less than in air, which matches …
A ray bends towards the normal on entering a second medium. What does this imply about the speed of light in the second medium?
Answer
If r < i, then the speed in the second medium is less than the speed in the first medium. Using Snell’s law from wave speeds: 1. sin i = BC/AC = v1τ/AC 2. sin r = AE/AC = v2τ/AC 3. sin i / sin r = v1…
एक किरण दूसरे माध्यम में प्रवेश करते समय अभिलम्ब की ओर मुड़ती है। इससे दूसरे माध्यम में प्रकाश की चाल के बारे में क्या संकेत मिलता है?
Answer
यदि r < i, तो दूसरे माध्यम में चाल पहले माध्यम की चाल से कम है। तरंग चालों से Snell’s law का उपयोग करते हुए: 1. sin i = BC/AC = v1τ/AC 2. sin r = AE/AC = v2τ/AC 3. sin i / sin r = v1 / v2 इसलिए, जब …
एक प्रकाश तरंग 3.0 × 10^8 m/s चाल वाले माध्यम से 2.0 × 10^8 m/s चाल वाले माध्यम में जाती है। तरंगदैर्घ्यों का अनुपात λ1/λ2 ज्ञात कीजिए।
Answer
दिया है: - v1 = 3.0 × 10^8 m/s - v2 = 2.0 × 10^8 m/s सूत्र: - v1/λ1 = v2/λ2 - इसलिए, λ1/λ2 = v1/v2 गणना: - λ1/λ2 = (3.0 × 10^8 m/s) / (2.0 × 10^8 m/s) - λ1/λ2 = 3/2 = 1.5 उत्तर: λ1/λ2 = 1.5…
A light wave goes from a medium of speed 3.0 × 10^8 m/s to a medium of speed 2.0 × 10^8 m/s. Find the ratio of wavelengths λ1/λ2.
Answer
Given: - v1 = 3.0 × 10^8 m/s - v2 = 2.0 × 10^8 m/s Formula: - v1/λ1 = v2/λ2 - Therefore, λ1/λ2 = v1/v2 Calculation: - λ1/λ2 = (3.0 × 10^8 m/s) / (2.0 × 10^8 m/s) - λ1/λ2 = 3/2 = 1.5 Answer: λ1/λ2 =…
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