Electric Charges and Fields — Flashcards
Madhya Pradesh Board · Class 12 · Physics
68 flashcards for Electric Charges and Fields (Madhya Pradesh Board Class 12 Physics) to test yourself on key terms and facts.
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Numerical: If 10^9 electrons leave a body every second, how long is needed to collect 1 C of charge?
Answer
Given: electron charge = 1.602192 × 10^-19 C, electrons per second = 10^9 s^-1. Step 1: Charge leaving each second = 1.602192 × 10^-19 × 10^9 C = 1.602192 × 10^-10 C/s. Step 2: Time = 1 C ÷ 1.602192 ×…
संख्यात्मक: यदि 10^9 इलेक्ट्रॉन हर सेकंड किसी पिंड को छोड़ते हैं, तो 1 C आवेश इकट्ठा करने में कितना समय लगेगा?
Answer
दिया गया है: इलेक्ट्रॉन का आवेश = 1.602192 × 10^-19 C, प्रति सेकंड इलेक्ट्रॉन = 10^9 s^-1. चरण 1: हर सेकंड निकलने वाला आवेश = 1.602192 × 10^-19 × 10^9 C = 1.602192 × 10^-10 C/s. चरण 2: समय = 1 C ÷ 1.6…
अवधारणात्मक: रेशम से रगड़ी गई काँच की छड़ धनावेशित क्यों हो जाती है?
Answer
जब काँच को रेशम से रगड़ा जाता है, तो इलेक्ट्रॉन काँच की छड़ से रेशम में चले जाते हैं। इलेक्ट्रॉनों की हानि से काँच की छड़ धनावेशित और रेशम ऋणावेशित हो जाती है। कोई नया आवेश उत्पन्न नहीं होता; आवेश केव…
Conceptual: Why does a glass rod rubbed with silk become positively charged?
Answer
When glass is rubbed with silk, electrons move from the glass rod to the silk. Loss of electrons leaves the glass rod positively charged and the silk negatively charged. No new charge is created; char…
State Coulomb’s law in its final scalar form.
Answer
F = (1/4πε0) |q1 q2| / r^2. It gives the magnitude of the electrostatic force between two point charges separated by distance r in vacuum. Unit check: F in newton, q in coulomb, r in metre, ε0 in C^2 …
कूलॉम के नियम को उसके अंतिम अदिश रूप में लिखिए।
Answer
F = (1/4πε0) |q1 q2| / r^2. यह निर्वात में दूरी r से अलग किए गए दो बिंदु आवेशों के बीच स्थितिज विद्युत बल का परिमाण देता है। इकाई जाँच: F न्यूटन में, q कूलॉम में, r मीटर में, ε0 C^2 N^-1 m^-2 में।…
संख्यात्मक: निर्वात में 1 m दूरी पर रखे गए दो 1 C आवेशों के बीच बल ज्ञात कीजिए।
Answer
दिया गया है: q1 = 1 C, q2 = 1 C, r = 1 m, k ≈ 9 × 10^9 N m^2 C^-2. सूत्र: F = k |q1 q2| / r^2. चरण 1: F = 9 × 10^9 × |1 × 1| / 1^2 N. चरण 2: F = 9 × 10^9 N. उत्तर: 9 × 10^9 N, प्रतिकर्षी।…
Numerical: Find the force between two 1 C charges placed 1 m apart in vacuum.
Answer
Given: q1 = 1 C, q2 = 1 C, r = 1 m, k ≈ 9 × 10^9 N m^2 C^-2. Formula: F = k |q1 q2| / r^2. Step 1: F = 9 × 10^9 × |1 × 1| / 1^2 N. Step 2: F = 9 × 10^9 N. Answer: 9 × 10^9 N, repulsive.
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