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Electric Charges and Fields

Madhya Pradesh Board · Class 12 · Physics

Flashcards for Electric Charges and Fields — Madhya Pradesh Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

141 questions68 flashcards5 concepts

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A comparison diagram illustrating the key difference between conductors and insulators at an atomic level, focusing on the availability and movement of free electrons.
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68 Flashcards
Card 1Quantisation of charge

Numerical: If 10^9 electrons leave a body every second, how long is needed to collect 1 C of charge?

Answer

Given: electron charge = 1.602192 × 10^-19 C, electrons per second = 10^9 s^-1. Step 1: Charge leaving each second = 1.602192 × 10^-19 × 10^9 C = 1.602192 × 10^-10 C/s. Step 2: Time = 1 C ÷ 1.602192 ×

Card 2आवेश का क्वांटीकरण

संख्यात्मक: यदि 10^9 इलेक्ट्रॉन हर सेकंड किसी पिंड को छोड़ते हैं, तो 1 C आवेश इकट्ठा करने में कितना समय लगेगा?

Answer

दिया गया है: इलेक्ट्रॉन का आवेश = 1.602192 × 10^-19 C, प्रति सेकंड इलेक्ट्रॉन = 10^9 s^-1. चरण 1: हर सेकंड निकलने वाला आवेश = 1.602192 × 10^-19 × 10^9 C = 1.602192 × 10^-10 C/s. चरण 2: समय = 1 C ÷ 1.6

Card 3घर्षण द्वारा आवेशन

अवधारणात्मक: रेशम से रगड़ी गई काँच की छड़ धनावेशित क्यों हो जाती है?

Answer

जब काँच को रेशम से रगड़ा जाता है, तो इलेक्ट्रॉन काँच की छड़ से रेशम में चले जाते हैं। इलेक्ट्रॉनों की हानि से काँच की छड़ धनावेशित और रेशम ऋणावेशित हो जाती है। कोई नया आवेश उत्पन्न नहीं होता; आवेश केव

Card 4Charging by rubbing

Conceptual: Why does a glass rod rubbed with silk become positively charged?

Answer

When glass is rubbed with silk, electrons move from the glass rod to the silk. Loss of electrons leaves the glass rod positively charged and the silk negatively charged. No new charge is created; char

Card 5Coulomb’s law

State Coulomb’s law in its final scalar form.

Answer

F = (1/4πε0) |q1 q2| / r^2. It gives the magnitude of the electrostatic force between two point charges separated by distance r in vacuum. Unit check: F in newton, q in coulomb, r in metre, ε0 in C^2

Card 6कूलॉम का नियम

कूलॉम के नियम को उसके अंतिम अदिश रूप में लिखिए।

Answer

F = (1/4πε0) |q1 q2| / r^2. यह निर्वात में दूरी r से अलग किए गए दो बिंदु आवेशों के बीच स्थितिज विद्युत बल का परिमाण देता है। इकाई जाँच: F न्यूटन में, q कूलॉम में, r मीटर में, ε0 C^2 N^-1 m^-2 में।

Card 7कूलॉम का नियम

संख्यात्मक: निर्वात में 1 m दूरी पर रखे गए दो 1 C आवेशों के बीच बल ज्ञात कीजिए।

Answer

दिया गया है: q1 = 1 C, q2 = 1 C, r = 1 m, k ≈ 9 × 10^9 N m^2 C^-2. सूत्र: F = k |q1 q2| / r^2. चरण 1: F = 9 × 10^9 × |1 × 1| / 1^2 N. चरण 2: F = 9 × 10^9 N. उत्तर: 9 × 10^9 N, प्रतिकर्षी।

Card 8Coulomb’s law

Numerical: Find the force between two 1 C charges placed 1 m apart in vacuum.

Answer

Given: q1 = 1 C, q2 = 1 C, r = 1 m, k ≈ 9 × 10^9 N m^2 C^-2. Formula: F = k |q1 q2| / r^2. Step 1: F = 9 × 10^9 × |1 × 1| / 1^2 N. Step 2: F = 9 × 10^9 N. Answer: 9 × 10^9 N, repulsive.

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What are the important topics in Electric Charges and Fields for Madhya Pradesh Board Class 12 Physics?
Electric Charges and Fields covers several key topics that are frequently asked in Madhya Pradesh Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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