Alternating Current — Flashcards
Madhya Pradesh Board · Class 12 · Physics
76 flashcards for Alternating Current (Madhya Pradesh Board Class 12 Physics) to test yourself on key terms and facts.
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प्रत्यावर्ती वोल्टेज के लिए समीकरण लिखिए और उसके पदों की परिभाषा दीजिए।
Answer
समीकरण: v = v_m sin ωt. यहाँ, v तात्क्षणिक वोल्टेज है, v_m आयाम है, ω कोणीय आवृत्ति है, और t समय है। वोल्टेज समय के साथ साइनाकार रूप से बदलता है।…
State the equation for alternating voltage and define its terms.
Answer
Equation: v = v_m sin ωt. Here, v is instantaneous voltage, v_m is amplitude, ω is angular frequency, and t is time. The voltage changes sinusoidally with time.
A 220 V rms AC supply is used in a home. Find the peak voltage.
Answer
Given: V = 220 V rms. Formula: V = v_m/√2, so v_m = √2 V. Step 1: v_m = 1.414 × 220 V Step 2: v_m = 311 V Answer: Peak voltage = 311 V.
एक 220 V rms AC आपूर्ति का उपयोग घर में किया जाता है। शिखर वोल्टेज ज्ञात कीजिए।
Answer
दिया है: V = 220 V rms. सूत्र: V = v_m/√2, इसलिए v_m = √2 V. चरण 1: v_m = 1.414 × 220 V चरण 2: v_m = 311 V उत्तर: शिखर वोल्टेज = 311 V.
rms धारा और शिखर धारा के बीच संबंध लिखिए।
Answer
सूत्र: I = i_m/√2 = 0.707 i_m. rms धारा वह प्रभावी धारा है जो DC धारा के समान औसत ऊष्मीय प्रभाव उत्पन्न करती है।…
State the relation between rms current and peak current.
Answer
Formula: I = i_m/√2 = 0.707 i_m. RMS current is the effective current that produces the same average heating effect as a DC current.
A resistor has R = 484 Ω and is connected to a 220 V rms supply. Find the rms current.
Answer
Given: R = 484 Ω, V = 220 V. Formula: V = IR Step 1: I = V/R Step 2: I = 220 V / 484 Ω Step 3: I = 0.454 A Answer: rms current = 0.454 A.
एक प्रतिरोधक का R = 484 Ω है और उसे 220 V rms आपूर्ति से जोड़ा गया है। rms धारा ज्ञात कीजिए।
Answer
दिया है: R = 484 Ω, V = 220 V. सूत्र: V = IR चरण 1: I = V/R चरण 2: I = 220 V / 484 Ω चरण 3: I = 0.454 A उत्तर: rms धारा = 0.454 A.
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