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Magnetism and Matter

Madhya Pradesh Board · Class 12 · Physics

Flashcards for Magnetism and Matter — Madhya Pradesh Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

98 questions60 flashcards5 concepts

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A comparison chart (table-like infographic) summarizing the key properties of diamagnetic, paramagnetic, and ferromagnetic materials, including their magnetic susceptibility, relative permeability, be
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60 Flashcards
Card 1Magnetic field lines

State the properties of magnetic field lines.

Answer

1. Magnetic field lines form continuous closed loops. 2. The tangent at any point gives the direction of the net magnetic field B. 3. Closer field lines mean a stronger magnetic field. 4. Magnetic fie

Card 2चुंबकीय क्षेत्र रेखाएँ

चुंबकीय क्षेत्र रेखाओं के गुण बताइए।

Answer

1. चुंबकीय क्षेत्र रेखाएँ सतत बंद लूप बनाती हैं। 2. किसी भी बिंदु पर खींची गई स्पर्शरेखा शुद्ध चुंबकीय क्षेत्र B की दिशा देती है। 3. जितनी पास-पास क्षेत्र रेखाएँ होंगी, चुंबकीय क्षेत्र उतना ही प्रबल ह

Card 3चुंबकत्व के लिए गॉस का नियम

चुंबकीय क्षेत्र रेखाएँ बंद लूप क्यों बनाती हैं?

Answer

चुंबकीय क्षेत्र रेखाएँ बंद लूप बनाती हैं क्योंकि अकेले चुंबकीय उत्तर या दक्षिण ध्रुव अस्तित्व में नहीं होते। किसी चुंबक में दोनों ध्रुव होते हैं, इसलिए क्षेत्र रेखाएँ उत्तर ध्रुव से निकलती हैं और दक्ष

Card 4Gauss law for magnetism

Why do magnetic field lines form closed loops?

Answer

Magnetic field lines form closed loops because isolated magnetic north or south poles do not exist. A magnet has both poles, so field lines leave the north pole and enter the south pole, continuing in

Card 5Torque on magnetic dipole

A short bar magnet has magnetic moment 0.50 J T^-1 and is placed in a uniform magnetic field of 0.20 T at 30 degrees. Find the torque.

Answer

Given: m = 0.50 J T^-1, B = 0.20 T, theta = 30 degrees Formula: tau = mB sin theta Step 1: tau = 0.50 x 0.20 x sin 30 degrees Step 2: sin 30 degrees = 0.5 Step 3: tau = 0.50 x 0.20 x 0.5 = 0.05 N m An

Card 6चुंबकीय द्विध्रुव पर आघूर्ण

एक छोटे बार चुंबक का चुंबकीय आघूर्ण 0.50 J T^-1 है और उसे 30 degrees पर 0.20 T के एकसमान चुंबकीय क्षेत्र में रखा गया है। आघूर्ण ज्ञात कीजिए।

Answer

दिया है: m = 0.50 J T^-1, B = 0.20 T, theta = 30 degrees सूत्र: tau = mB sin theta चरण 1: tau = 0.50 x 0.20 x sin 30 degrees चरण 2: sin 30 degrees = 0.5 चरण 3: tau = 0.50 x 0.20 x 0.5 = 0.05 N m उत्तर

Card 7चुंबकीय द्विध्रुव पर आघूर्ण

एकसमान चुंबकीय क्षेत्र में चुंबकीय द्विध्रुव पर आघूर्ण का सूत्र बताइए।

Answer

सूत्र: tau = m x B परिमाण: tau = mB sin theta यहाँ, tau का अर्थ N m में आघूर्ण है, m का अर्थ A m^2 में चुंबकीय आघूर्ण है, B का अर्थ टेस्ला में चुंबकीय क्षेत्र है, और theta का अर्थ m तथा B के बीच का को

Card 8Torque on magnetic dipole

State the formula for torque on a magnetic dipole in a uniform magnetic field.

Answer

Formula: tau = m x B Magnitude: tau = mB sin theta Here, tau is torque in N m, m is magnetic moment in A m^2, B is magnetic field in tesla, and theta is the angle between m and B.

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What are the important topics in Magnetism and Matter for Madhya Pradesh Board Class 12 Physics?
Magnetism and Matter covers several key topics that are frequently asked in Madhya Pradesh Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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