Work, Energy and power — Flashcards
ICSE · Class 10 · Physics
36 flashcards for Work, Energy and power (ICSE Class 10 Physics) to test yourself on key terms and facts. Sample: "What is work in physics?"
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See them allWhat is work in physics?
Answer
Work is done only when a body is displaced under the influence of an applied force. Formula: W = F·d Also, W = Fs cosθ Meaning: - F = force - d = displacement - θ = angle between force and displacem…
Why is no work done when a man pushes a wall?
Answer
No work is done because there is no displacement of the wall. Reason: - Force acts - Displacement is zero - So, W = F × 0 = 0 J This is a common zero-work case.
A coolie carries a load while walking on a level platform. Why is the work done against gravity zero?
Answer
The load moves horizontally, while gravity acts vertically downward. Angle between force and displacement = 90° So, W = Fs cos90° = 0 This is zero work due to perpendicular force and displacement.
A force of 10 N moves a body by 5 m in the same direction. Find work done.
Answer
Given: - Force, F = 10 N - Displacement, s = 5 m - Angle, θ = 0° Formula: W = Fs Step 1: Substitute values W = 10 N × 5 m Step 2: Calculate W = 50 N m Answer: 50 J…
A force of 20 N acts on a body displaced by 3 m at an angle of 60°. Find work done.
Answer
Given: - F = 20 N - s = 3 m - θ = 60° Formula: W = F cosθ · s Step 1: cos60° = 1/2 Step 2: W = 20 × (1/2) × 3 Step 3: W = 10 × 3 = 30 N m Answer: 30 J…
When is work maximum, zero, and negative?
Answer
- Maximum work: when force and displacement are in the same direction, θ = 0° W = Fs - Zero work: when force and displacement are perpendicular, θ = 90° W = 0 - Negative work: when force and displ…
A body is pulled by 15 N opposite to its motion through 4 m. Find work done.
Answer
Given: - F = 15 N - s = 4 m - θ = 180° Formula: W = -Fs Step 1: Substitute values W = -15 × 4 Step 2: Calculate W = -60 N m Answer: -60 J…
State the SI and CGS units of work.
Answer
- SI unit of work: joule (J) - CGS unit of work: erg Relations: - 1 J = 10^7 erg - 1 erg = work done by 1 dyne in moving a body by 1 cm - 1 J = work done by 1 newton in moving a body by 1 m…
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