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Chapter 8 of 30
Important Questions

Surface Tension — Important Questions

ICSE · Class 11 · Physics

44 important questions from Surface Tension for ICSE Class 11 Physics, with answers. Includes multiple choice questions. Covers Surface Energy, Work Done.

44 questions28 flashcards9 formulas & key relations5 concepts

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44 Questions·
multiple choice

Important Questions from Surface Tension

1multiple choice
1 marks

A capillary tube of radius r is dipped in water at an angle of contact θ. The water rises to a height h. If the tube is now inclined at an angle α to the vertical, the vertical height of water in the tube is:

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h (unchanged)

Step 1: The capillary rise formula gives the VERTICAL height h = 2T cos θ / (rρg). Step 2: This height h depends only on T, θ, r, ρ, and g — none of which change when the tube is tilted. Step 3: When inclined, the vertical height of water remains h (same as before). Step 4: However, the LENGTH of liquid column along the inclined tube increases to h/cos α. Step 5: So the vertical height stays h, but the length of the liquid in the tube becomes longer. A common mistake is confusing the length of liquid in the tube with the vertical height.

2multiple choice
1 marks

The work done in increasing the surface area of a soap film by 20 cm² is 4 × 10⁻⁴ J. What is the surface tension of the soap solution?

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0.01 N/m

Step 1: Recall that surface tension T = Work done / Increase in area. Step 2: A soap film has TWO surfaces, so total increase in area = 2 × 20 cm² = 40 cm² = 40 × 10⁻⁴ m². Step 3: Given work done W = 4 × 10⁻⁴ J. Step 4: Surface tension T = W / ΔA = (4 × 10⁻⁴) / (40 × 10⁻⁴) = 4/40 = 0.1... Wait — recalculate: ΔA = 40 × 10⁻⁴ m²; T = 4 × 10⁻⁴ / 40 × 10⁻⁴ = 0.1 N/m. Actually: 20 cm² = 20 × 10⁻⁴ m²; two surfaces → 40 × 10⁻⁴ m²; T = 4 × 10⁻⁴ / 40 × 10⁻⁴ = 0.1... Correction: T = 4×10⁻⁴ / (2 × 20×10⁻⁴) = 4×10⁻⁴ / 40×10⁻⁴ = 0.1 N/m. Let us re-verify the question: with W = 4×10⁻⁴ J and ΔA_total = 40×10⁻

3multiple choice
1 marks

Two soap bubbles of radii r₁ = 2 cm and r₂ = 4 cm are formed. The ratio of excess pressure inside the smaller bubble to that inside the larger bubble is:

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2:1

Step 1: For a soap bubble, excess pressure p = 4T/R. Step 2: Excess pressure is inversely proportional to radius (p ∝ 1/R). Step 3: For the smaller bubble: p₁ = 4T/r₁ = 4T/0.02. Step 4: For the larger bubble: p₂ = 4T/r₂ = 4T/0.04. Step 5: Ratio p₁/p₂ = r₂/r₁ = 4/2 = 2:1. So the smaller bubble has higher excess pressure — this is why when two soap bubbles are connected, air flows from the smaller bubble to the larger bubble, making the smaller one shrink and the larger one grow.

4multiple choice
1 marks

The angle of contact for water and clean glass is approximately 0°, while for mercury and glass it is 135°. What does this imply about the shape of the meniscus in a glass capillary for water and mercury respectively?

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Concave for water, convex for mercury

Step 1: The shape of the meniscus depends on the angle of contact θ. Step 2: For water-glass: adhesive force (water-glass) > cohesive force (water-water), so θ ≈ 0° (acute). The resultant force on surface molecules points outward (away from water), making the meniscus concave (curved upward). Step 3: A concave meniscus causes capillary RISE in water. Step 4: For mercury-glass: cohesive force (mercury-mercury) > adhesive force (mercury-glass), so θ = 135° (obtuse). The resultant force points inward, making the meniscus convex (curved downward). Step 5: A convex meniscus causes capillary DEPRESS

+40 more questions on Surface Tension (ICSE Class 11 Physics)

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Frequently Asked Questions

What are the important topics in Surface Tension for ICSE Class 11 Physics?
Key topics in Surface Tension include Surface tension is the property, Cohesive force is the force, Adhesive force is the force, The maximum distance up to. Study these first, then practise questions on each for Class 11 exams.
How many important questions are there in Surface Tension?
Super Tutor has 44 practice questions for Surface Tension, including multiple choice questions. A sample with answers is on this page.

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