Flow of Liquids — Important Questions
ICSE · Class 11 · Physics
41 important questions from Flow of Liquids for ICSE Class 11 Physics, with answers. Includes multiple choice questions.
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Important Questions from Flow of Liquids
What are the SI unit and dimensions of the coefficient of viscosity (η)?
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Unit: kg m⁻¹ s⁻¹ ; Dimensions: [M L⁻¹ T⁻¹]
From the formula η = F / [A × (dv/dz)]: Step 1: Dimensions of F = [M L T⁻²]. Step 2: Dimensions of A = [L²]. Step 3: Dimensions of dv/dz = [L T⁻¹ / L] = [T⁻¹]. Step 4: Therefore η = [M L T⁻²] / ([L²][T⁻¹]) = [M L T⁻²] / [L² T⁻¹] = [M L⁻¹ T⁻¹]. The SI unit is kg m⁻¹ s⁻¹, also called 1 decapoise = 10 poise. Option B is wrong (dimensions of momentum per unit area). Option C is wrong (these are dimensions of pressure). Option D has an extra negative power of L.
Stokes' law gives the viscous force on a small sphere of radius r moving with terminal velocity v through a medium of viscosity η. Which formula correctly represents Stokes' law?
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F = 6π η r v
Stokes' law states that the viscous (drag) force on a small sphere moving through a homogeneous medium is F = 6π η r v. Here η is the coefficient of viscosity of the medium, r is the radius of the sphere, and v is the velocity of the sphere. Option A is wrong (coefficient is 4π, not 6π). Option C is wrong (r should be to the power 1, not r²). Option D is wrong (v should be to the power 1, not v²). The number 6π comes from the mathematical derivation by Stokes for a sphere.
The Principle of Continuity states that for a liquid flowing through a tube of non-uniform cross-section, the product A × v is constant. If water flows through a pipe of cross-sectional area 4 cm² at a velocity of 3 m/s, what is the velocity at a constriction where the area is 2 cm²?
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6 m/s
Principle of Continuity: A₁v₁ = A₂v₂. Step 1: Write given values — A₁ = 4 cm², v₁ = 3 m/s, A₂ = 2 cm². Step 2: Apply continuity equation — 4 × 3 = 2 × v₂. Step 3: Solve for v₂ — v₂ = 12/2 = 6 m/s. The velocity doubles when the area is halved. Option A (1.5 m/s) is wrong — this would be the answer if the student divided instead of multiplied (thinking velocity decreases when area decreases). Option B (3 m/s) is wrong — velocity is not constant throughout. Option D (12 m/s) is wrong — this comes from v₂ = A₁ × v₁ without dividing by A₂.
Bernoulli's theorem for a flowing liquid can be written as P + ½ρv² + ρgh = constant. What does each term in this equation represent (per unit volume)?
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P = pressure energy, ½ρv² = kinetic energy, ρgh = potential energy
In Bernoulli's equation, each term represents energy per unit volume: (1) P is the pressure energy per unit volume (work done by pressure forces). (2) ½ρv² is the kinetic energy per unit volume (since KE per unit volume = ½(m/V)v² = ½ρv²). (3) ρgh is the potential energy per unit volume (since PE per unit volume = (m/V)gh = ρgh). Bernoulli's theorem is essentially the law of conservation of energy for a flowing ideal liquid. All other options incorrectly assign the terms.
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