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Chapter 12 of 30
Important Questions

Heat Transfer

ICSE · Class 11 · Physics

Most important questions from Heat Transfer for ICSE Class 11 Physics board exam 2026. MCQs, short answer, and long answer questions with marks.

42 questions32 flashcards5 concepts

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42 Questions·
multiple choice

Sample Questions

1multiple choice
1 marks

In Searle's method to find thermal conductivity, four thermometers T₁, T₂, T₃, T₄ are used. Which thermometers measure the temperature of the rod, and which measure the temperature of flowing water?

Show answer

T₁, T₂ measure rod temperature; T₃, T₄ measure water temperature

Step 1: In Searle's apparatus, thermometers T₁ and T₂ are inserted into holes C and D drilled in the rod itself (with mercury for good thermal contact). They record the steady-state temperature gradient along the rod. Step 2: Thermometers T₃ and T₄ measure the inlet and outlet temperatures of the cooling water flowing through the spiral copper tube wound at the cold end. Step 3: The formula K = mc(θ₄ - θ₃)l / [A(θ₁ - θ₂)t] uses all four readings to calculate K. The wrong options confuse the arrangement of the thermometers.

2multiple choice
1 marks

A black body at 727°C emits heat at a certain rate. If its temperature is reduced to 227°C, the new rate of heat emission will be what fraction of the original rate?

Show answer

1/16

Step 1: Convert temperatures to Kelvin: T₁ = 727 + 273 = 1000 K, T₂ = 227 + 273 = 500 K. Step 2: By Stefan's law, E ∝ T⁴. So E₂/E₁ = (T₂/T₁)⁴ = (500/1000)⁴ = (1/2)⁴ = 1/16. Step 3: The new emission rate is 1/16 of the original. Common error: Using Celsius instead of Kelvin gives (227/727)⁴ ≈ 1/136, which is wrong. Always convert to Kelvin for Stefan's law.

3multiple choice
1 marks

Two slabs of equal length l and same cross-sectional area A are connected in parallel. Their thermal conductivities are K₁ and K₂. What is the equivalent thermal conductivity?

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(K₁ + K₂) / 2

Step 1: For parallel combination with equal areas A₁ = A₂ = A, the equivalent conductivity formula is: K = (K₁A₁ + K₂A₂) / (A₁ + A₂). Step 2: With A₁ = A₂ = A: K = (K₁A + K₂A) / (2A) = (K₁ + K₂) / 2. This is the arithmetic mean of the two conductivities. Wrong options: K₁K₂/(K₁+K₂) is the formula for electrical resistors in parallel; 2K₁K₂/(K₁+K₂) is the formula for series combination of equal-thickness slabs; (K₁+K₂) is not a valid formula.

4multiple choice
1 marks

A hot body at temperature T is placed in a room at temperature T₀. According to Newton's law of cooling, the rate of fall of temperature of the body is proportional to:

Show answer

T - T₀

Step 1: Newton's law of cooling states that the rate of loss of heat is proportional to the temperature difference between the body and its surroundings: -dQ/dt ∝ (T - T₀). Step 2: Since dQ = ms dT, this gives: -dT/dt = K(T - T₀), where K is a positive constant. Step 3: So the rate of fall of temperature is proportional to (T - T₀), which is the simple temperature difference. Note: The T⁴ - T₀⁴ term appears in Stefan-Boltzmann law for net radiation, not in Newton's law of cooling. Newton's law is valid only for small temperature differences.

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Frequently Asked Questions

What are the important topics in Heat Transfer for ICSE Class 11 Physics?
Key topics in Heat Transfer include Heat Transfer Methods and Properties, Heat Transfer: Complete Chapter Overview, Heat Transfer - Comprehensive Concept Map. These are the concepts ICSE Class 11 examiners draw on most — study them first, then practise related questions.
How to score full marks in Heat Transfer — ICSE Class 11 Physics?
Understand the core concepts first, then work through the 42 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many important questions are there in Heat Transfer?
There are 42 practice questions available for Heat Transfer. These cover multiple question types including MCQs, short answer, and long answer questions.

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