Rotational Motion of a Rigid Body: Moment of Inertia
ICSE · Class 11 · Physics
Most important questions from Rotational Motion of a Rigid Body: Moment of Inertia for ICSE Class 11 Physics board exam 2026. MCQs, short answer, and long answer questions with marks.
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A body has angular momentum 24 kg m²/s and moment of inertia 8.0 kg m². If the angular momentum remains constant and the moment of inertia becomes 6.0 kg m², what is the new angular velocity?
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4.0 rad/s
Since L = Iω remains constant, first confirm L = 24 kg m²/s. For the new situation, ω = L/I = 24/6.0 = 4.0 rad/s.
A ring of mass 4.0 kg and radius 0.50 m rotates about its central axis perpendicular to its plane with angular velocity 10 rad/s. What is its rotational kinetic energy?
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50 J
For a ring about its central axis, I = MR² = 4.0 × 0.50² = 4.0 × 0.25 = 1.0 kg m². Then K = 1/2 Iω² = 1/2 × 1.0 × 10² = 50 J.
A rigid body has moment of inertia 9.0 kg m² and rotational kinetic energy 72 J. What is its angular velocity?
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4.0 rad/s
Use K = 1/2 Iω². So 72 = 1/2 × 9.0 × ω² = 4.5ω². Hence ω² = 16 and ω = 4.0 rad/s.
A body with angular momentum 30 kg m²/s has its moment of inertia reduced from 10 kg m² to 6.0 kg m² without external torque. What is the ratio of the final angular velocity to the initial angular velocity?
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5/3
With no external torque, Iω is constant. So I₁ω₁ = I₂ω₂. Therefore ω₂/ω₁ = I₁/I₂ = 10/6 = 5/3.
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