Surface Tension — Flashcards
ICSE · Class 11 · Physics
28 flashcards for Surface Tension (ICSE Class 11 Physics) to test yourself on key terms and facts. Sample: "State the definition of surface tension."
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State the definition of surface tension.
Answer
Surface tension is defined as force per unit length acting at right angles on either side of an imaginary line in the liquid surface. Formula: T = F/l Here, T = surface tension, F = force, l = length …
A force of 0.24 N acts along an imaginary line of length 0.12 m on a liquid surface. Find the surface tension.
Answer
Given: F = 0.24 N l = 0.12 m Formula: T = F/l Solution: T = 0.24 N / 0.12 m T = 2.0 N/m Answer: 2.0 N/m Check: Unit = N/m, which is correct.
Why does a liquid surface tend to acquire minimum area?
Answer
A surface molecule experiences an unbalanced inward pull because molecules inside the liquid attract it from all sides, while molecules outside the surface are absent. As a result, the surface tends t…
State the relation between surface tension and work done in increasing surface area.
Answer
Relation: W = T × ΔA and T = W/ΔA Here, W = work done, ΔA = increase in surface area. Meaning: Surface tension is equal to the work required to increase the surface area of a liquid film by unity at c…
A soap film gains an extra area of 0.50 m². If the surface tension is 0.040 N/m, find the work done.
Answer
Given: ΔA = 0.50 m² T = 0.040 N/m Formula: W = T × ΔA Solution: W = 0.040 N/m × 0.50 m² W = 0.020 N·m W = 0.020 J Answer: 0.020 J…
State the SI unit and dimensional formula of surface tension.
Answer
SI unit: N/m Dimensional formula: [MT^-2] Surface tension can also be expressed in J/m^2 because it is work done per unit area increase.
Why are liquid drops and bubbles spherical?
Answer
Liquid drops and bubbles are spherical because a sphere has minimum surface area for a given volume. This helps the liquid surface attain minimum energy. Small mercury drops are spherical for the same…
A liquid drop has radius 0.002 m and surface tension 0.030 N/m. Find the excess pressure inside the drop.
Answer
Given: R = 0.002 m T = 0.030 N/m Formula: p = 2T/R Solution: p = (2 × 0.030 N/m) / 0.002 m p = 0.060 / 0.002 N/m² p = 30 N/m² p = 30 Pa Answer: 30 Pa…
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