Skip to main content
Chapter 27 of 30
Important Questions

Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns — Important Questions

ICSE · Class 11 · Physics

52 important questions from Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns for ICSE Class 11 Physics, with answers.

52 questions34 flashcards12 formulas & key relations5 concepts

Interactive on Super Tutor

Studying Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for important questions and more.

Free trial, no card needed.

Illustrates a transverse wave pulse traveling along a string and reflecting from a free end. The reflected pulse is shown with no phase change (not inverted) compared to the incident pulse.
Super Tutor

An illustration from Super Tutor's Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns chapter — alongside flashcards, concept maps and practice questions.

52 Questions·
multiple choicemultiple correct

Important Questions from Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns

1multiple choice
3 marks

A closed pipe has length 0.60 m and radius 0.05 m. If the speed of sound is 340 m/s, what is its fundamental frequency using end correction?

Show answer

132.8 Hz

For a closed pipe with end correction, n1 = v / 4(l + 0.6r). Here 0.6r = 0.6 × 0.05 = 0.03 m. Effective length = 0.60 + 0.03 = 0.63 m. So n1 = 340 / (4 × 0.63) = 340 / 2.52 ≈ 132.8 Hz.

2multiple choice
3 marks

A closed pipe has length 0.50 m and speed of sound 340 m/s. What is the difference between its first and second harmonic frequencies?

Show answer

340 Hz

For a closed pipe, consecutive harmonics differ by Δn = 2n1 = 2v / 4l. So Δn = 2 × 340 / (4 × 0.50) = 680 / 2 = 340 Hz.

3multiple choice
3 marks

A tuning fork of frequency 256 Hz is used in a resonance tube. If the first resonance length is 0.30 m, what is the second resonance length neglecting end correction?

Show answer

0.90 m

For a resonance tube, l1 = λ/4 and l2 = 3λ/4. So l2 = 3l1. If l1 = 0.30 m, then l2 = 0.90 m.

4multiple choice
3 marks

A tuning fork of frequency 400 Hz produces first and second resonance lengths of 0.21 m and 0.63 m in a resonance tube. What is the wavelength of sound?

Show answer

0.84 m

Use λ = 2(l2 - l1). Here l2 - l1 = 0.63 - 0.21 = 0.42 m. So λ = 2 × 0.42 = 0.84 m.

+48 more questions on Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns (ICSE Class 11 Physics)

Practise All

Frequently Asked Questions

What are the important topics in Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns for ICSE Class 11 Physics?
Key topics in Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns include Bounded Medium and Reflection of Waves, Stationary Waves: Formation and Properties, Closed Organ Pipe, Open Organ Pipe. Study these first, then practise questions on each for Class 11 exams.
How many important questions are there in Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns?
Super Tutor has 52 practice questions for Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns, including multiple choice, multiple correct questions. A sample with answers is on this page.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Superposition of Waves-2 : Stationary (Standing) Waves : Vibration of Air Columns chapter — start free.

Quizzes, flashcards, an AI doubt solver and a study plan for ICSE Class 11 Physics. Free to start, no card needed.