Superposition of Waves-1 : Interference and Beats — Practice Quiz
ICSE · Class 11 · Physics
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Quick Quiz: Superposition of Waves-1 : Interference and Beats
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A point in an interference pattern has a path difference of 0.060 m for waves of wavelength 0.020 m. What type of interference occurs at that point?
Two coherent sound waves have intensities 9 units and 4 units and meet with phase difference 0. What is the resultant intensity?
Two coherent waves of equal amplitude 5 cm have phase difference π. What is the resultant amplitude?
Two sound waves have frequencies 256 Hz and 254 Hz. After superposition, how many beats per second are heard?
Sample Questions
A tuning fork of frequency 300 Hz is sounded with an unknown fork and 5 beats per second are heard. After loading the unknown fork with wax, the number of beats decreases. What was the original frequency of the unknown fork?
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305 Hz
If beats decrease after loading with wax, the unknown fork was originally higher in frequency than 300 Hz. Since 5 beats per second are heard, the frequency difference is 5 Hz. Therefore, the unknown frequency is 300 + 5 = 305 Hz.
In Quinck's tube, the tube C is moved outward by 1.5 cm. By how much does the path difference change?
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3.0 cm
In Quinck's tube, sliding tube C by λ/4 changes the path difference by λ/2. So the path difference changes by twice the slide distance. For 1.5 cm movement, change in path difference = 2 × 1.5 cm = 3.0 cm.
A Galton's whistle of frequency 512 Hz is used in Quinck's tube. If the wavelength found is 0.67 m, what is the speed of sound?
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343.04 m/s
Speed of sound is v = nλ. Here n = 512 Hz and λ = 0.67 m. So v = 512 × 0.67 = 343.04 m/s.
Two sound waves with frequencies 440 Hz and 435 Hz are superposed. What is the time interval between two consecutive maxima of intensity?
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0.2 s
Time interval between two consecutive maxima = 1/(n1 - n2). Here difference = 440 - 435 = 5 Hz. So interval = 1/5 = 0.2 s.
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