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Nuclear Fission and Nuclear Fusion: Source of Energy

ICSE · Class 12 · Physics

Flashcards for Nuclear Fission and Nuclear Fusion: Source of Energy — ICSE Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

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A step-by-step diagram illustrating the process of nuclear fission, specifically a chain reaction initiated by a neutron striking a Uranium-235 nucleus, leading to the release of energy and more neutr
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36 Flashcards
Card 1Nuclear fission

State the definition of nuclear fission.

Answer

Nuclear fission is a process in which a heavy nucleus, after capturing a thermal neutron having energy 0.027 eV, splits up into two lighter nuclei of comparable masses. The product nuclei are called f

Card 2Discovery of fission

Who observed the splitting of uranium nucleus when it was bombarded with neutrons, and who named the process nuclear fission?

Answer

Hahn and Strassmann observed that uranium nucleus with Z = 92, when bombarded with neutrons, split into isotopes of barium and krypton. Meitner and Frisch named the phenomenon nuclear fission.

Card 3Fissionability of uranium isotopes

Why can U-235 sustain a chain reaction more easily than U-238?

Answer

U-235 can be fissioned by slow or thermal neutrons of about 0.03 eV. U-238 can only be fissioned by fast neutrons above 1 MeV, and below 1 MeV it absorbs neutrons without fission. This makes U-235 muc

Card 4Fission mechanism

A slow neutron strikes U-235. What are the main steps of the fission process?

Answer

Step 1: U-235 captures a slow neutron and forms unstable U-236. Step 2: U-236 splits into two lighter nuclei. Step 3: Two or three fast neutrons are emitted. Step 4: A large amount of energy is releas

Card 5Fission fragments

What is the typical mass-number range of fission fragments?

Answer

The fission fragments are radioactive isotopes of elements lying in the mass-number range roughly from 70 to 160. They undergo several beta decays until they reach stable end-products.

Card 6Energy conversion in fission

A U-235 nucleus releases about 200 MeV per fission. Convert this into joules.

Answer

Given: Energy per fission = 200 MeV Formula: 1 MeV = 1.6 × 10^-13 J Calculation: 200 × 1.6 × 10^-13 J = 3.2 × 10^-11 J Answer: 3.2 × 10^-11 J per fission

Card 7Energy from 1 g U-235

Calculate the energy released if 1 g of U-235 is fully fissioned.

Answer

Given: 1 g of U-235 = 2.56 × 10^21 atoms Energy per fission = 200 MeV = 3.2 × 10^-11 J Step 1: Total energy in joules = (2.56 × 10^21) × (3.2 × 10^-11 J) Step 2: E = 8.19 × 10^10 J approximately Answe

Card 8Chain reaction factor

State the formula for multiplication or reproduction factor K.

Answer

K = (Number of neutrons present at the beginning of present generation) / (Number of neutrons in the beginning of previous generation) Meaning: K tells whether a chain reaction is steady, increasing,

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