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NCERT Solutions

The Human Eye and the Colourful World

Madhya Pradesh Board · Class 10 · Science

NCERT Solutions for The Human Eye and the Colourful World — Madhya Pradesh Board Class 10 Science.

56 questions72 flashcards5 concepts

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12 Questions Solved · 1 Section

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EXERCISES

1The human eye can focus on objects at different distances by adjusting the focal length of the eye lens. This is due toShow solution
The ability of the eye lens to adjust its focal length so that we can see objects at different distances clearly is called accommodation.

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2The human eye forms the image of an object at itsShow solution
The eye lens forms the image on a light-sensitive screen called the retina.

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3The least distance of distinct vision for a young adult with normal vision is aboutShow solution
For a young adult with normal vision, the near point or least distance of distinct vision is about 25 cm.

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4The change in focal length of an eye lens is caused by the action of theShow solution
The ciliary muscles change the curvature of the eye lens, and thus change its focal length.

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5A person needs a lens of power –5.5 dioptres for correcting his distant vision. For correcting his near vision he needs a lens of power +1.5 dioptre. What is the focal length of the lens required for correcting (i) distant vision, and (ii) near vision?Show solution
Use P=1fP=\frac{1}{f}, with ff in metres.

For distant vision:
P=−5.5 DP=-5.5\,D

f=1P=1−5.5 m=−0.1818 m=−18.2 cmf=\frac{1}{P}=\frac{1}{-5.5}\,m=-0.1818\,m=-18.2\,cm

For near vision:
P=+1.5 DP=+1.5\,D

f=11.5 m=0.6667 m=66.7 cmf=\frac{1}{1.5}\,m=0.6667\,m=66.7\,cm

So the focal lengths are -18.2 cm and +66.7 cm.

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6The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?Show solution
A myopic eye forms the image of distant objects in front of the retina. It is corrected by a concave lens.

Given far point = 80 cm=0.8 m80\,cm = 0.8\,m.
For correction, the lens should form the image of a distant object at the far point, so
f=−0.8 mf = -0.8\,m (negative for concave lens).

Power,
P=1f=1−0.8=−1.25 DP=\frac{1}{f}=\frac{1}{-0.8}=-1.25\,D

So the required lens is a concave lens of power -1.25 dioptre.

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7Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.
8Why is a normal eye not able to see clearly the objects placed closer than 25 cm?
9What happens to the image distance in the eye when we increase the distance of an object from the eye?
10Why do stars twinkle?
11Explain why the planets do not twinkle.
12Why does the sky appear dark instead of blue to an astronaut?

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Frequently Asked Questions

What are the important topics in The Human Eye and the Colourful World for Madhya Pradesh Board Class 10 Science?
Key topics in The Human Eye and the Colourful World include Human Eye and Vision - Complete Chapter Overview, The Human Eye and Colourful World - Complete Overview, The Human Eye and Colourful World - Complete Concept Map. These are the concepts Madhya Pradesh Board Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in The Human Eye and the Colourful World — Madhya Pradesh Board Class 10 Science?
Understand the core concepts first, then work through the 56 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
Where can I get free NCERT Solutions for The Human Eye and the Colourful World Class 10 Science?
This page has free step-by-step NCERT Solutions for every exercise question in The Human Eye and the Colourful World (Madhya Pradesh Board Class 10 Science) — written the way examiners award marks: given, formula, working, answer.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

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