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Angles In A Circle And Cyclic Quadrilateral

NIOS · Class 10 · Maths

Flashcards for Angles In A Circle And Cyclic Quadrilateral — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.

41 questions28 flashcards5 concepts

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A diagram illustrating the definitions of central angle and inscribed angle, showing an arc, the center of the circle, and a point on the remaining part of the circle.
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28 Flashcards
Card 1Central angle and inscribed angle

Solve: In a circle, the central angle subtended by an arc is 70°. Find the inscribed angle subtended by the same arc.

Answer

Step 1: Use the relation central angle = 2 × inscribed angle. Step 2: Let the inscribed angle be x. Step 3: 70° = 2x Step 4: x = 70°/2 = 35° Answer: The inscribed angle is 35°.

Card 2Central angle and inscribed angle

Solve: The inscribed angle subtended by an arc is 28°. Find the central angle subtended by the same arc.

Answer

Step 1: Use central angle = 2 × inscribed angle. Step 2: Central angle = 2 × 28° Step 3: Central angle = 56° Answer: The central angle is 56°.

Card 3Minor arc and major arc

Solve: A minor arc has degree measure 125°. Find the degree measure of its corresponding major arc.

Answer

Step 1: Degree measure of major arc = 360° minus degree measure of corresponding minor arc. Step 2: Major arc = 360° - 125° Step 3: Major arc = 235° Answer: The major arc measures 235°.

Card 4Arc length formula

When do you use the formula Length of an arc = circumference × (degree measure of the arc)/360°? Show one example.

Answer

Use this formula when the arc measure and radius are known and the length of only part of the circle is needed. Example: If an arc measures 40° and the radius is r, then Length of arc = 2πr × 40°/360°

Card 5Arc length calculation

Solve: A circle has radius 9 cm. Find the length of an arc whose degree measure is 80°.

Answer

Step 1: Use Length of an arc = circumference × degree measure/360°. Step 2: Circumference = 2πr = 2π × 9 = 18π cm. Step 3: Arc length = 18π × 80/360 Step 4: Arc length = 18π × 2/9 Step 5: Arc length =

Card 6Angle in a semicircle

Why is the angle in a semicircle always a right angle?

Answer

Step 1: The angle at the centre subtended by a semicircle is 180°. Step 2: The central angle is double the inscribed angle. Step 3: So, 2 × inscribed angle = 180°. Step 4: Inscribed angle = 90°. Answe

Card 7Angle in a semicircle

Solve: In a semicircle, an inscribed angle is formed at the circle. Find its measure.

Answer

Step 1: The angle subtended at the centre by a semicircle is 180°. Step 2: Central angle = 2 × inscribed angle. Step 3: 180° = 2x Step 4: x = 90° Answer: The angle is 90°.

Card 8Angles in the same segment

Solve: Two angles subtended by the same chord in the same segment are 42° and x°. Find x.

Answer

Step 1: Angles in the same segment of a circle are equal. Step 2: So the two angles must be equal. Step 3: x = 42° Answer: x = 42°.

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Frequently Asked Questions

What are the important topics in Angles In A Circle And Cyclic Quadrilateral for NIOS Class 10 Maths?
Key topics in Angles In A Circle And Cyclic Quadrilateral include Circle Angles Concept Map, Angles in Circle - Complete Overview, Circle Angles and Cyclic Quadrilaterals Concept Map. These are the concepts NIOS Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Angles In A Circle And Cyclic Quadrilateral — NIOS Class 10 Maths?
Understand the core concepts first, then work through the 41 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Angles In A Circle And Cyclic Quadrilateral?
There are 28 flashcards for Angles In A Circle And Cyclic Quadrilateral covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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