Co-Ordinate Geometry
NIOS · Class 10 · Maths
Flashcards for Co-Ordinate Geometry — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.
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See them allFind the co-ordinates of the point whose x-coordinate is 3 and y-coordinate is 4.
Answer
Step 1: Write the first number as the x-coordinate. Step 2: Write the second number as the y-coordinate. Answer: The point is (3, 4).
What is the co-ordinate of the origin?
Answer
The origin is the point where the x-axis and y-axis intersect. Answer: (0, 0).
Find the distance of point (5, 6) from the y-axis and from the x-axis.
Answer
Step 1: The first number gives distance from the y-axis. Step 2: The second number gives distance from the x-axis. For (5, 6): distance from y-axis = 5 units, distance from x-axis = 6 units. Answer: 5…
Why are the points (3, 4) and (4, 3) generally different positions?
Answer
The order of numbers matters in co-ordinates. In (3, 4), x = 3 and y = 4. In (4, 3), x = 4 and y = 3. These are different points because the horizontal and vertical distances are different. Answer: In…
Which quadrant contains the point (-3, 4)?
Answer
Step 1: x is negative. Step 2: y is positive. Quadrant signs are: I (+,+), II (-,+), III (-,-), IV (+,-). Answer: Quadrant II.
Classify the point (4, -1) into the correct quadrant.
Answer
Step 1: x is positive. Step 2: y is negative. Quadrant signs are: I (+,+), II (-,+), III (-,-), IV (+,-). Answer: Quadrant IV.
Find the distance between P(6, 8) and Q(-9, -12).
Answer
Use the distance formula: PQ = square root of ((x2 - x1)^2 + (y2 - y1)^2) Step 1: Substitute the values. PQ = square root of ((-9 - 6)^2 + (-12 - 8)^2) Step 2: Simplify. PQ = square root of ((-15)^2 +…
Find the distance between A(-6, -1) and B(-6, 11).
Answer
Use the distance formula: AB = square root of ((x2 - x1)^2 + (y2 - y1)^2) Step 1: Substitute the values. AB = square root of ((-6 - (-6))^2 + (11 - (-1))^2) Step 2: Simplify. AB = square root of (0^2 …
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