Trigonometric Ratios Of Some Special Angles
NIOS · Class 10 · Maths
Flashcards for Trigonometric Ratios Of Some Special Angles — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Trigonometric Ratios Of Some Special Angles? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 10 students started this chapter today

Super Tutor has 7+ illustrations like this for Trigonometric Ratios Of Some Special Angles alone — flashcards, concept maps, and step-by-step visuals.
See them allSolve: In a right triangle, if one acute angle is 45° and one side adjacent to it is a units, find the hypotenuse.
Answer
Step 1: For 45°, the two legs are equal, so the other leg is also a units. Step 2: Use Pythagoras theorem: hypotenuse^2 = a^2 + a^2 = 2a^2. Step 3: Hypotenuse = sqrt(2)a. Answer: The hypotenuse is sqr…
Find sin 45°, cos 45°, tan 45°, cosec 45°, sec 45°, and cot 45°.
Answer
Step 1: In a 45°-45°-90° triangle, both legs are equal and the hypotenuse is sqrt(2) times one leg. Step 2: sin 45° = 1/sqrt(2). Step 3: cos 45° = 1/sqrt(2). Step 4: tan 45° = 1. Step 5: cosec 45° = s…
Solve: In the 30° construction, if PM = a units, find OP and OM.
Answer
Step 1: In the 30° construction, the triangle formed becomes equilateral with side 2a. Step 2: Therefore OP = 2a units. Step 3: Use Pythagoras theorem in the right triangle: OP^2 = PM^2 + OM^2. Step 4…
Find sin 30°, cos 30°, tan 30°, cosec 30°, sec 30°, and cot 30°.
Answer
Step 1: Use the 30° special triangle values. Step 2: sin 30° = 1/2. Step 3: cos 30° = sqrt(3)/2. Step 4: tan 30° = 1/sqrt(3). Step 5: cosec 30° = 2. Step 6: sec 30° = 2/sqrt(3). Step 7: cot 30° = sqrt…
Solve: In the 60° construction, if OM = a units, find PM and OP.
Answer
Step 1: In the 60° construction, the triangle formed becomes equilateral with side 2a. Step 2: Therefore OP = 2a units. Step 3: Use Pythagoras theorem in the right triangle: OP^2 = OM^2 + PM^2. Step 4…
Find sin 60°, cos 60°, tan 60°, cosec 60°, sec 60°, and cot 60°.
Answer
Step 1: Use the 60° special triangle values. Step 2: sin 60° = sqrt(3)/2. Step 3: cos 60° = 1/2. Step 4: tan 60° = sqrt(3). Step 5: cosec 60° = 2/sqrt(3). Step 6: sec 60° = 2. Step 7: cot 60° = 1/sqrt…
Evaluate: tan^2 60° - sin^2 30°
Answer
Step 1: tan 60° = sqrt(3), so tan^2 60° = 3. Step 2: sin 30° = 1/2, so sin^2 30° = 1/4. Step 3: Subtract: 3 - 1/4 = 11/4. Answer: 11/4.
Evaluate: cot^2 30° sec^2 45° + cosec^2 45° cos 60°
Answer
Step 1: cot 30° = sqrt(3), so cot^2 30° = 3. Step 2: sec 45° = sqrt(2), so sec^2 45° = 2. Step 3: cosec 45° = sqrt(2), so cosec^2 45° = 2. Step 4: cos 60° = 1/2. Step 5: Compute: (3)(2) + (2)(1/2) = 6…
+16 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Trigonometric Ratios Of Some Special Angles for NIOS Class 10 Maths?
How to score full marks in Trigonometric Ratios Of Some Special Angles — NIOS Class 10 Maths?
How many flashcards are available for Trigonometric Ratios Of Some Special Angles?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Trigonometric Ratios Of Some Special Angles
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Trigonometric Ratios Of Some Special Angles chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for NIOS Class 10 Maths.