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Introduction To Trigonometry

NIOS · Class 10 · Maths

Flashcards for Introduction To Trigonometry — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.

42 questions24 flashcards5 concepts

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24 Flashcards
Card 1Trigonometric ratios

In right triangle ABC, right-angled at B, if AB = 4 cm, BC = 3 cm, and AC = 5 cm, find sin A, cos A, tan A, cosec A, sec A, and cot A.

Answer

Step 1: For angle A, opposite side = BC = 3 cm, adjacent side = AB = 4 cm, hypotenuse = AC = 5 cm. Step 2: Use the ratios. • sin A = BC/AC = 3/5 • cos A = AB/AC = 4/5 • tan A = BC/AB = 3/4 • cosec A =

Card 2Trigonometric ratios

In right triangle ABC, right-angled at B, AB = 5 cm, BC = 12 cm, and AC = 13 cm. Find tan C, cosec C, and sec C.

Answer

Step 1: For angle C, opposite side = AB = 5 cm, adjacent side = BC = 12 cm, hypotenuse = AC = 13 cm. Step 2: Apply the formulas. • tan C = AB/BC = 5/12 • cosec C = AC/AB = 13/5 • sec C = AC/BC = 13/12

Card 3Trigonometric ratios

In right triangle ABC, right-angled at B, AB = 9 cm, BC = 40 cm, and AC = 41 cm. Find cos C, cot C, tan A, and cosec A.

Answer

Step 1: For angle C, adjacent side = BC = 40 cm, opposite side = AB = 9 cm, hypotenuse = AC = 41 cm. Step 2: For angle A, opposite side = BC = 40 cm, adjacent side = AB = 9 cm. Step 3: Apply the formu

Card 4Pythagoras and ratios

In right triangle ABC, right-angled at B, AB = 4 cm and BC = 3 cm. Find AC, then find sin C, cos C, cot C, tan A, sec A, and cosec A.

Answer

Step 1: Use Pythagoras Theorem. AC^2 = AB^2 + BC^2 AC^2 = 4^2 + 3^2 = 16 + 9 = 25 AC = 5 cm Step 2: For angle C. • sin C = AB/AC = 4/5 • cos C = BC/AC = 3/5 • cot C = BC/AB = 3/4 Step 3: For angle A.

Card 5Pythagoras and ratios

In right triangle PQR, right-angled at Q, PQ = 5 cm and QR = 12 cm. Find PR, then find sin R, cos R, and tan R.

Answer

Step 1: Use Pythagoras Theorem. PR^2 = PQ^2 + QR^2 PR^2 = 5^2 + 12^2 = 25 + 144 = 169 PR = 13 cm Step 2: For angle R. • opposite side = PQ = 5 cm • adjacent side = QR = 12 cm • hypotenuse = PR = 13 cm

Card 6Pythagoras and ratios

In right triangle PQR, right-angled at Q, PR = 25 cm and PQ = 7 cm. Find QR, then find tan R, cosec R, and sec R.

Answer

Step 1: Use Pythagoras Theorem. QR^2 = PR^2 - PQ^2 QR^2 = 25^2 - 7^2 = 625 - 49 = 576 QR = 24 cm Step 2: For angle R. • opposite side = PQ = 7 cm • adjacent side = QR = 24 cm • hypotenuse = PR = 25 cm

Card 7Given one ratio

If sin theta = 12/13, find the other five trigonometric ratios of theta.

Answer

Step 1: Write the ratio as opposite/hypotenuse. Let opposite side = 12k and hypotenuse = 13k. Step 2: Find the adjacent side using Pythagoras Theorem. Adjacent^2 = 13^2k^2 - 12^2k^2 = 169k^2 - 144k^2

Card 8Given one ratio

If cos theta = 7/25, find sin theta and tan theta.

Answer

Step 1: Write cos theta as adjacent/hypotenuse. Let adjacent side = 7k and hypotenuse = 25k. Step 2: Find the opposite side using Pythagoras Theorem. Opposite^2 = 25^2k^2 - 7^2k^2 = 625k^2 - 49k^2 = 5

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Frequently Asked Questions

What are the important topics in Introduction To Trigonometry for NIOS Class 10 Maths?
Key topics in Introduction To Trigonometry include Trigonometric Ratios Overview, Trigonometry Concepts Overview, Trigonometric Ratios Overview. These are the concepts NIOS Class 10 examiners draw on most — study them first, then practise related questions.
How to score full marks in Introduction To Trigonometry — NIOS Class 10 Maths?
Understand the core concepts first, then work through the 42 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Introduction To Trigonometry?
There are 24 flashcards for Introduction To Trigonometry covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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