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Solutions

ICSE · Class 12 · Chemistry

Flashcards for Solutions — ICSE Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

100 questions40 flashcards5 concepts

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An infographic illustrating different types of solutions based on the physical state of solute and solvent, including gaseous, liquid, and solid solutions, with common examples for each.
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40 Flashcards
Card 1Introduction to solutions

What is a solution?

Answer

A solution is a homogeneous mixture of two or more substances. Example: sugar dissolved in water forms a homogeneous liquid solution.

Card 2Components of a solution

What is the solvent and what is the solute?

Answer

The component present in excess and whose physical state is the same as that of the solution is called the solvent. The other component present in smaller amount is called the solute. Example: in suga

Card 3Types of solutions

What are binary, ternary, and quaternary solutions?

Answer

Binary solutions have 2 components, ternary solutions have 3 components, and quaternary solutions have 4 components.

Card 4Types of solutions

Why is solid always treated as the solute in solid-liquid solutions?

Answer

In solid-liquid solutions, solid is always considered as the solute, regardless of relative amounts. Example: salt in water is a solid-liquid solution, so salt is the solute.

Card 5Concentration units

What is mass percentage of a solute?

Answer

Mass percentage of solute = (Mass of solute / Mass of solution) × 100 Mass of solution = Mass of solute + Mass of solvent Example: 10 g solute in 100 g solution gives 10% by mass.

Card 6Concentration calculations

Calculate the mass percentage if 10 g of urea is dissolved in 100 g of solution.

Answer

Mass percentage = (Mass of solute / Mass of solution) × 100 = (10 g / 100 g) × 100 = 10% Answer: 10% (by mass)

Card 7Concentration units

What is molarity and why does it change with temperature?

Answer

Molarity (M) = number of moles of solute dissolved per litre of solution at a particular temperature. M = n / V It changes with temperature because volume changes with temperature.

Card 8Concentration calculations

Calculate the molarity of a solution containing 4 g NaOH in 200 cm³ of solution.

Answer

Given: mass of NaOH = 4 g, molar mass = 40 g mol⁻¹, volume = 200 cm³ = 0.2 L Step 1: moles = 4/40 = 0.1 mol Step 2: M = n/V = 0.1/0.2 = 0.5 mol L⁻¹ Answer: 0.5 M

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Frequently Asked Questions

What are the important topics in Solutions for ICSE Class 12 Chemistry?
Key topics in Solutions include Solutions: Complete Concept Map, Complete Overview of Solutions Chapter, A pie chart showing the relative abundance of different solution types commonly encountered. These are the concepts ICSE Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Solutions — ICSE Class 12 Chemistry?
Understand the core concepts first, then work through the 100 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Solutions?
There are 40 flashcards for Solutions covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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