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Chapter 16 of 32
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Diffraction of Light

ICSE · Class 12 · Physics

Flashcards for Diffraction of Light — ICSE Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions28 flashcards5 concepts

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28 Flashcards
Card 1Definition of diffraction

State the definition of diffraction.

Answer

Diffraction is the bending of light round the corners of obstacles or apertures. It is a characteristic of wave-motion.

Card 2Condition for diffraction

When is diffraction of light strong?

Answer

Diffraction is strong only when the size of the obstacle or aperture is of the order of the wavelength of light. If the slit is widened much more, diffraction becomes weak and light propagates nearly

Card 3Effect of diffraction

Why does the image of a point source appear as a disc?

Answer

Due to diffraction, light spreads around the aperture and does not remain perfectly confined to a point. As a result, the image of a point source appears as a disc rather than a point.

Card 4Colour dependence of diffraction

Why does red light diffract more than blue light?

Answer

Red light diffracts more than blue light because red light has a longer wavelength. A larger wavelength gives a larger angular spread in diffraction.

Card 5Minimum condition

State the first minimum condition for single-slit diffraction.

Answer

First minimum condition: e sin θ = λ Here, e = slit width, θ = diffraction angle, and λ = wavelength.

Card 6First minimum numerical

A slit of width 1.0 × 10^-6 m is illuminated by light of wavelength 500 nm. Find the angle of the first minimum.

Answer

Given: e = 1.0 × 10^-6 m, λ = 500 nm = 5.0 × 10^-7 m Formula: e sin θ = λ Step 1: sin θ = λ/e = (5.0 × 10^-7 m)/(1.0 × 10^-6 m) = 0.5 Step 2: θ = sin^-1(0.5) = 30° Answer: The first minimum occurs at

Card 7Minima condition

State the general condition of minima in single-slit diffraction.

Answer

General condition of minima: e sin θ = ±mλ, where m = 1, 2, 3, ... The value m = 0 does not give a minimum; it corresponds to the principal maximum.

Card 8First minimum numerical

A slit of width 0.50 mm is illuminated by light of wavelength 650 nm. Find the angle of the first minimum.

Answer

Given: e = 0.50 mm = 0.50 × 10^-3 m, λ = 650 nm = 650 × 10^-9 m Formula: e sin θ = λ Step 1: sin θ = λ/e = (650 × 10^-9 m)/(0.50 × 10^-3 m) = 1.3 × 10^-3 Step 2: θ is very small, so θ ≈ 1.3 × 10^-3 ra

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What are the important topics in Diffraction of Light for ICSE Class 12 Physics?
Key topics in Diffraction of Light include Diffraction of Light - Concept Hierarchy, Diffraction of Light - Complete Concept Map, Diffraction of Light – Complete Chapter Mind Map. These are the concepts ICSE Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Diffraction of Light — ICSE Class 12 Physics?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Diffraction of Light?
There are 28 flashcards for Diffraction of Light covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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