Electromagnetic Induction — Flashcards
ICSE · Class 12 · Physics
30 flashcards for Electromagnetic Induction (ICSE Class 12 Physics) to test yourself on key terms and facts. Part of the ICSE Class 12 Physics syllabus.
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State Faraday’s first law of electromagnetic induction.
Answer
Faraday’s first law: When the magnetic flux through a circuit is changing, an induced emf is set up in the circuit whose magnitude is equal to the negative rate of change of magnetic flux. Formula: e …
State Faraday’s second law and Lenz’s law.
Answer
Faraday’s second law: The direction of the induced emf, or the current, in any circuit is such as to oppose the cause that produces it. This is also called Lenz’s law. Meaning: the induced current res…
A magnetic flux through a coil changes by 0.094 Wb in 10^-3 s. Find the induced emf for 100 turns.
Answer
Given: N = 100 ΔΦ_B = 0.094 Wb Δt = 10^-3 s Formula: e = -N(ΔΦ_B/Δt) Step 1: magnitude of emf = 100 × (0.094 / 10^-3) V Step 2: = 100 × 94 V Step 3: = 9400 V Answer: magnitude of induced emf = 9400 V.
A coil of resistance 10 Ω has an induced emf of 31 mV. Find the induced current.
Answer
Given: e = 31 mV = 31 × 10^-3 V R = 10 Ω Formula: I = e/R Step 1: I = (31 × 10^-3 V) / (10 Ω) Step 2: I = 3.1 × 10^-3 A Step 3: I = 3.1 mA Answer: induced current = 3.1 mA. Unit check: V/Ω = A.
Why does a faster moving magnet produce a larger galvanometer deflection in a coil?
Answer
A faster motion means a larger rate of change of magnetic flux through the coil. From Faraday’s law, e is proportional to dΦ_B/dt, so larger flux change per second gives larger induced emf. If the cir…
A coil has 500 turns, resistance 50 Ω, and total change in flux 0.094 Wb. Find the charge flowing through it.
Answer
Given: N = 500 R = 50 Ω ΔΦ_B = 0.094 Wb Formula: q = (N/R)ΔΦ_B Step 1: q = (500/50) × 0.094 C Step 2: q = 10 × 0.094 C Step 3: q = 0.94 C Answer: charge flowed = 0.94 C. Important idea: induced charge…
Why does induced charge not depend on the time taken for the flux change?
Answer
For a closed circuit, I = e/R and e = -N(dΦ_B/dt). So q = IΔt = (N/R)(ΔΦ_B). The time interval cancels out. Therefore, the total charge depends only on the change in magnetic flux and the resistance.
A rod of length 0.5 m moves at 2 m/s perpendicular to a magnetic field of 0.15 T. Find the motional emf.
Answer
Given: B = 0.15 T v = 2 m/s l = 0.5 m Formula: V = Bvl Step 1: V = 0.15 × 2 × 0.5 V Step 2: V = 0.15 V Answer: motional emf = 0.15 V. Unit check: T × m/s × m = V.
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