Magnetic Classification of Substances — Flashcards
ICSE · Class 12 · Physics
28 flashcards for Magnetic Classification of Substances (ICSE Class 12 Physics) to test yourself on key terms and facts.
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A magnetising field produces a magnetic flux of 2.4 × 10^-5 Wb in an iron bar of cross-sectional area 0.2 cm². Find the magnetic induction B.
Answer
Given: Φ = 2.4 × 10^-5 Wb, A = 0.2 cm² = 0.2 × 10^-4 m² = 2.0 × 10^-5 m² Formula: B = Φ / A Step 1: B = (2.4 × 10^-5 Wb) / (2.0 × 10^-5 m²) Step 2: B = 1.2 Wb m^-2 Step 3: B = 1.2 T Answer: 1.2 T…
An iron bar has B = 1.2 T and H = 1600 A m^-1. Find the permeability μ and susceptibility χm.
Answer
Given: B = 1.2 T, H = 1600 A m^-1 Formula: μ = B / H Step 1: μ = 1.2 / 1600 Step 2: μ = 7.5 × 10^-4 N A^-2 Formula: μ = μ0(1 + χm) Step 3: χm = (μ / μ0) - 1 Step 4: χm = (7.5 × 10^-4) / (4π × 10^-7) -…
An iron rod has susceptibility 599 and is placed in a magnetising field H = 1200 A m^-1. Find μ and the magnetic flux through cross-sectional area 0.2 cm².
Answer
Given: χm = 599, H = 1200 A m^-1, A = 0.2 cm² = 2.0 × 10^-5 m² Formula: μ = μ0(1 + χm) Step 1: μ = 4π × 10^-7 × (1 + 599) T m A^-1 Step 2: μ = 4π × 10^-7 × 600 Step 3: μ = 7.536 × 10^-4 T m A^-1 Formu…
A paramagnetic salt contains 2.0 × 10^24 atomic magnets, each of moment 1.5 × 10^-23 J T^-1. In a field of 0.84 T at 4.2 K, it shows 15% saturation. Find the total magnetic moment at 0.98 T and 2.8 K,
Answer
Given: number of atomic magnets = 2.0 × 10^24, moment of each = 1.5 × 10^-23 J T^-1 Maximum possible moment = (2.0 × 10^24)(1.5 × 10^-23) J T^-1 = 30 J T^-1 Initial saturation = 15% Step 1: m1 = (15/1…
A paramagnetic gas has atomic moment 1.5 × 10^-23 A m² and number density 2.0 × 10^26 m^-3. Find the maximum possible magnetisation.
Answer
Given: m = 1.5 × 10^-23 A m², number density = 2.0 × 10^26 m^-3 Formula: M = magnetic moment per unit volume Step 1: M = m × number density Step 2: M = (1.5 × 10^-23)(2.0 × 10^26) A m^-1 Step 3: M = 3…
A paramagnetic gas at 27°C is placed in a field of 3.0 T. Its atomic magnetic energy is 4.5 × 10^-23 J and thermal energy is (3/2)kT = 6.2 × 10^-21 J. Compare them and state whether complete alignment
Answer
Given: thermal energy = 6.2 × 10^-21 J, magnetic energy = 4.5 × 10^-23 J Step 1: Ratio = (6.2 × 10^-21) / (4.5 × 10^-23) Step 2: Ratio ≈ 138 Interpretation: thermal energy is about 138 times larger th…
Why is every substance, in general, diamagnetic?
Answer
Every substance has electrons, and paired electrons have opposite spins. Their magnetic moments cancel, so the atom has no net moment in the absence of an external field. When a field is applied, the …
Why does a diamagnetic rod suspended freely between two magnetic poles set itself perpendicular to the magnetic field?
Answer
A diamagnetic substance is feebly magnetised opposite to the applied field. In a uniform field, the rod experiences a couple that turns its axis perpendicular to the field. This orientation makes the …
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