Magnetic Field and Earth's Magnetism
ICSE · Class 12 · Physics
Flashcards for Magnetic Field and Earth's Magnetism — ICSE Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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State the magnetic dipole moment of a current loop and a coil with N turns.
Answer
Magnetic dipole moment of a current loop: m = IA, where I is current in ampere and A is area in square metre. Vector form: m→ = IA→. For N turns: m→ = NIA→. Unit: A-m². Dimensions: [AL²]. Quick check:…
A current loop carries 3 A and has area 0.2 m². Find its magnetic dipole moment.
Answer
Given: I = 3 A, A = 0.2 m² Formula: m = IA Substitution: m = 3 A × 0.2 m² Calculation: m = 0.6 A-m² Answer: 0.6 A-m² Unit is correct because current loop magnetic moment is measured in A-m².
Why does a current-carrying loop behave like a bar magnet?
Answer
A current loop produces a magnetic field and has north-like and south-like behaviour. In a magnetic field, it experiences torque and tends to align its axis parallel to the field, just like a bar magn…
A coil has 40 turns, current 0.5 A, and area 0.03 m². Find the magnetic moment.
Answer
Given: N = 40, I = 0.5 A, A = 0.03 m² Formula: m = NIA Substitution: m = 40 × 0.5 × 0.03 Step 1: 40 × 0.5 = 20 Step 2: 20 × 0.03 = 0.6 Answer: m = 0.6 A-m²…
State the torque on a magnetic dipole in a uniform magnetic field.
Answer
Torque on a magnetic dipole: τ = mB sinθ Vector form: τ→ = m→ × B→ Meaning: m is magnetic dipole moment, B is magnetic field, and θ is the angle between them. Maximum torque: τmax = mB when θ = 90°. I…
A magnetic dipole has moment 2 A-m² and is placed in a field of 0.4 T at 30°. Find the torque.
Answer
Given: m = 2 A-m², B = 0.4 T, θ = 30° Formula: τ = mB sinθ Substitution: τ = 2 × 0.4 × sin30° Use sin30° = 0.5 Calculation: τ = 0.8 × 0.5 = 0.4 N-m Answer: 0.4 N-m…
Why is torque maximum when the magnetic moment is perpendicular to the magnetic field?
Answer
Torque is given by τ = mB sinθ. The sine value is maximum at θ = 90°, where sin90° = 1. So the torque becomes τmax = mB. Physically, the field tries to turn the dipole to align it with the field, and …
A magnetic dipole has moment 1.5 A-m² in a field of 0.22 T. Find the work required to turn it from 0° to 90°.
Answer
Given: m = 1.5 A-m², B = 0.22 T For θ = 0°: U0 = -mB For θ = 90°: U90 = 0 Work required: W = U90 - U0 = 0 - (-mB) = mB Substitution: W = 1.5 × 0.22 Calculation: W = 0.33 J Answer: 0.33 J…
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