Refraction of light at a Plane Interface: Total Internal Reflection: Optical Fibre
ICSE · Class 12 · Physics
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State the definition of refraction of light.
Answer
Refraction is the bending of a light ray from its path when it passes from one transparent medium to another at the interface of the two media.
Why does refraction occur when light passes from one medium to another?
Answer
Refraction occurs because the speed of light changes from one medium to another. Greater the change in speed, greater is the bending of the ray.
State the two laws of refraction.
Answer
1) The incident ray, refracted ray, and the normal at the point of incidence lie in the same plane. 2) For a given pair of media and a given colour of light, sin i / sin r is constant.
State Snell's law in general form.
Answer
n1 sin i = n2 sin r, where n1 and n2 are the refractive indices of the first and second media, i is the angle of incidence, and r is the angle of refraction.
A ray enters glass from air with angle of incidence 30°. If the angle of refraction is 20°, find the refractive index of glass with respect to air.
Answer
Given: i = 30°, r = 20°. Formula: n = sin i / sin r. Step 1: sin 30° = 0.5. Step 2: sin 20° ≈ 0.342. Step 3: n = 0.5 / 0.342 ≈ 1.46. Answer: refractive index ≈ 1.46.
When angle of incidence is 0°, what happens to refraction?
Answer
When i = 0°, Snell's law gives r = 0°. So there is no bending of the ray at normal incidence.
State the formula for absolute refractive index and explain its meaning.
Answer
n = c / v. Here c is the velocity of light in vacuum and v is the velocity of light in the medium. It has no unit and is greater than 1 for a material medium.
A medium has refractive index 1.5. If c = 3 × 10^8 m/s, find the speed of light in the medium.
Answer
Given: n = 1.5, c = 3 × 10^8 m/s. Formula: n = c / v. Step 1: v = c / n. Step 2: v = (3 × 10^8 m/s) / 1.5 = 2 × 10^8 m/s. Answer: 2 × 10^8 m/s.
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