Chemical Kinetics — Flashcards
Tamil Nadu Board · Class 12 · Chemistry
40 flashcards for Chemical Kinetics (Tamil Nadu Board Class 12 Chemistry) to test yourself on key terms and facts.
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Define chemical kinetics and state what it studies.
Answer
Chemical kinetics is the branch of chemistry that studies the rate and mechanism of chemical reactions under given conditions of temperature, pressure, and concentration. It answers two key questions:…
Express the rate of the reaction: 2NO(g) + O₂(g) → 2NO₂(g) in terms of concentration changes.
Answer
Rate = -½(d[NO]/dt) = -(d[O₂]/dt) = ½(d[NO₂]/dt). This is because for every 2 moles of NO consumed, 1 mole of O₂ is consumed and 2 moles of NO₂ are formed. The stoichiometric coefficients in the denom…
Calculate the rate of a reaction given: At t=0, [A]=2.00 mol L⁻¹; at t=10 min, [A]=1.40 mol L⁻¹
Answer
Average Rate = -Δ[A]/Δt = -(1.40 - 2.00)/(10 - 0) = -(-0.60)/10 = 0.06 mol L⁻¹ min⁻¹. This represents the average rate over the 10-minute period. Note: The negative sign is used because reactant conce…
What is the difference between average rate and instantaneous rate?
Answer
Average rate is the change in concentration over a finite time interval (Δt), calculated as Δ[A]/Δt. Instantaneous rate is the rate at a specific moment, represented as d[A]/dt as Δt→0. Graphically, a…
Define rate constant (k) and state its key properties.
Answer
Rate constant (k) is the proportionality constant in the rate law equation. Properties: (1) It does not depend on the concentrations of reactants. (2) It depends only on temperature and the nature of …
Given experimental data for the reaction 2NO + Cl₂ → 2NOCl, determine the order with respect to each reactant and the overall order.
Answer
Experiment 1: [NO]=0.1 M, [Cl₂]=0.1 M, Rate=7.8×10⁻⁵ mol L⁻¹s⁻¹ Experiment 2: [NO]=0.2 M, [Cl₂]=0.1 M, Rate=3.12×10⁻⁴ mol L⁻¹s⁻¹ Experiment 3: [NO]=0.2 M, [Cl₂]=0.3 M, Rate=9.36×10⁻⁴ mol L⁻¹s⁻¹ Ratio…
What is the difference between order of reaction and molecularity?
Answer
Order of Reaction: (1) Determined experimentally from rate law, (2) Sum of powers of concentration terms in rate law, (3) Can be zero, fractional, or integer, (4) Applies to the overall reaction. Mole…
Derive the integrated rate equation for a first-order reaction A → products.
Answer
Starting with: Rate = -d[A]/dt = k[A]¹ Separating variables: -d[A]/[A] = kdt Integrating: ∫d[A]/[A] = ∫kdt ln[A] = -kt + C At t=0, [A]=[A₀], so C = ln[A₀] Final integrated form: ln([A₀]/[A]) = kt or l…
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