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Ionic Equilibrium

Tamil Nadu Board · Class 12 · Chemistry

Flashcards for Ionic Equilibrium — Tamil Nadu Board Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions30 flashcards5 concepts

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30 Flashcards
Card 1Acid-Base Theories

Define an acid according to Arrhenius concept with one example.

Answer

According to Arrhenius concept, an acid is a substance that dissociates to give hydrogen ions (H⁺ or H₃O⁺) in aqueous solution. Example: HCl(g) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq). Limitation: Does not expl

Card 2Acid-Base Theories

What is the Lowry-Bronsted definition of acids and bases? Give an example.

Answer

Lowry-Bronsted theory defines: Acid = proton (H⁺) donor; Base = proton acceptor. Example: HCl + H₂O ⇌ H₃O⁺ + Cl⁻. Here HCl is acid (donates H⁺), H₂O is base (accepts H⁺). Advantage: Explains basic beh

Card 3Acid-Base Theories

Define Lewis acids and bases. Identify each in: BF₃ + NH₃ → F₃B-NH₃

Answer

Lewis acid = electron pair acceptor; Lewis base = electron pair donor. In BF₃ + NH₃ → F₃B-NH₃: BF₃ is Lewis acid (has vacant 2p orbital, accepts electron pair), NH₃ is Lewis base (has lone pair on N,

Card 4Water Ionization

What is Kw (ionic product of water)? Calculate its value at 25°C.

Answer

Kw is the ionic product of water: Kw = [H₃O⁺][OH⁻]. Derivation: Pure water: H₂O ⇌ H₃O⁺ + OH⁻. Experimentally at 25°C, [H₃O⁺] = [OH⁻] = 1×10⁻⁷ M. Therefore: Kw = (1×10⁻⁷)(1×10⁻⁷) = 1×10⁻¹⁴. This is con

Card 5Water Ionization

Calculate [OH⁻] in a fruit juice with [H₃O⁺] = 2×10⁻³ M. Is it acidic or basic?

Answer

Using Kw = [H₃O⁺][OH⁻]. Step 1: [OH⁻] = Kw/[H₃O⁺] = (1×10⁻¹⁴)/(2×10⁻³) = 5×10⁻¹² M. Step 2: Compare: [H₃O⁺] = 2×10⁻³ >> [OH⁻] = 5×10⁻¹² M. Conclusion: Solution is ACIDIC because [H₃O⁺] > [OH⁻] (and >

Card 6pH Scale

Define pH scale. Calculate pH of 0.001 M HCl solution.

Answer

pH is defined as: pH = -log₁₀[H₃O⁺]. It measures hydrogen ion concentration on logarithmic scale. Calculation: HCl is strong acid, completely dissociates. [H₃O⁺] = 0.001 M = 10⁻³ M. pH = -log(10⁻³) =

Card 7pH Scale

Calculate pH of 10⁻⁷ M HCl. Why can't we ignore water ionization?

Answer

When acid concentration is very low (< 10⁻⁶ M), [H₃O⁺] from water ionization (10⁻⁷ M) becomes significant. Total [H₃O⁺] = 10⁻⁷ (from HCl) + 10⁻⁷ (from water) = 2×10⁻⁷ M. pH = -log(2×10⁻⁷) = 7 - log(2)

Card 8pH Scale

What is the relationship between pH and pOH? Derive it.

Answer

Starting with: pH = -log[H₃O⁺] and pOH = -log[OH⁻]. Adding both: pH + pOH = -log[H₃O⁺] - log[OH⁻] = -log([H₃O⁺][OH⁻]) = -log(Kw). At 25°C, Kw = 10⁻¹⁴, so: pH + pOH = -log(10⁻¹⁴) = 14. This relationshi

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What are the important topics in Ionic Equilibrium for Tamil Nadu Board Class 12 Chemistry?
Key topics in Ionic Equilibrium include Ionic Equilibrium – Complete Chapter Overview, Ionic Equilibrium - Concepts Hierarchy, Overview of Ionic Equilibrium - Key Topics. These are the concepts Tamil Nadu Board Class 12 examiners draw on most — study them first, then practise related questions.
How to score full marks in Ionic Equilibrium — Tamil Nadu Board Class 12 Chemistry?
Understand the core concepts first, then work through the 45 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
How many flashcards are available for Ionic Equilibrium?
There are 30 flashcards for Ionic Equilibrium covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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