Electrical Charges and Fields
Telangana Open School (TOSS) · Class 12 · Physics
Flashcards for Electrical Charges and Fields — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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State the basic properties of electric charges.
Answer
1. There are two types: positive and negative. 2. Like charges repel; unlike charges attract. 3. Charge is conserved: total charge in an isolated system remains constant. 4. Charge is quantised: it ex…
What happens when a glass rod is rubbed with silk? Explain the charge transfer.
Answer
Electrons are transferred from glass to silk. The glass rod loses electrons and becomes positively charged. The silk gains electrons and becomes negatively charged. This is due to friction, and the pr…
A glass rod acquires +3.2 × 10⁻¹⁷ C charge after being rubbed with silk. What is the charge on the silk cloth?
Answer
By conservation of charge, the silk gains equal and opposite charge. Given: q_glass = +3.2 × 10⁻¹⁷ C Therefore, q_silk = -3.2 × 10⁻¹⁷ C. Answer: -3.2 × 10⁻¹⁷ C…
How many electrons make up 1 coulomb of charge?
Answer
Formula: Q = ne ⇒ n = Q/e Given: Q = 1 C, e = 1.6 × 10⁻¹⁹ C n = 1 / (1.6 × 10⁻¹⁹) = 6.25 × 10¹⁸ electrons. Answer: 6.25 × 10¹⁸ electrons…
Is a charge of 2.5e possible? Why or why not?
Answer
No. Charge is quantised in integer multiples of e (1.6 × 10⁻¹⁹ C). Since 2.5 is not an integer, 2.5e is not allowed. Only charges like 1e, 2e, 3e are possible.
State Coulomb's Law.
Answer
The electrostatic force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. Formula: F = k(q₁q₂…
Two charges of 6.0 × 10⁻¹⁰ C each are separated by 2.0 m. Find the Coulomb force between them.
Answer
Given: q₁ = q₂ = 6.0 × 10⁻¹⁰ C, r = 2.0 m, k = 9 × 10⁹ Nm²/C² F = k(q₁q₂)/r² = (9 × 10⁹) × (6.0 × 10⁻¹⁰)² / (2.0)² = (9 × 10⁹) × (3.6 × 10⁻¹⁹) / 4 = (3.24 × 10⁻⁹) / 4 = 8.1 × 10⁻¹⁰ N Answer: 8.1 × 10⁻…
Two charges q₁ = 16 μC and q₂ = 9 μC are 12 m apart. Find the force on q₁ due to q₂.
Answer
Given: q₁ = 16 × 10⁻⁶ C, q₂ = 9 × 10⁻⁶ C, r = 12 m, k = 9 × 10⁹ F = k(q₁q₂)/r² = (9 × 10⁹) × (16 × 10⁻⁶) × (9 × 10⁻⁶) / (12)² = (9 × 10⁹) × (1.44 × 10⁻¹⁰) / 144 = (1.296 × 10⁰) / 144 = 0.009 N Force o…
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