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Electrical Charges and Fields

Telangana Open School (TOSS) · Class 12 · Physics

Flashcards for Electrical Charges and Fields — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

52 questions30 flashcards5 concepts

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Card 1Electric Charges

State the basic properties of electric charges.

Answer

1. There are two types: positive and negative. 2. Like charges repel; unlike charges attract. 3. Charge is conserved: total charge in an isolated system remains constant. 4. Charge is quantised: it ex

Card 2Frictional Electricity

What happens when a glass rod is rubbed with silk? Explain the charge transfer.

Answer

Electrons are transferred from glass to silk. The glass rod loses electrons and becomes positively charged. The silk gains electrons and becomes negatively charged. This is due to friction, and the pr

Card 3Conservation of Charge

A glass rod acquires +3.2 × 10⁻¹⁷ C charge after being rubbed with silk. What is the charge on the silk cloth?

Answer

By conservation of charge, the silk gains equal and opposite charge. Given: q_glass = +3.2 × 10⁻¹⁷ C Therefore, q_silk = -3.2 × 10⁻¹⁷ C. Answer: -3.2 × 10⁻¹⁷ C

Card 4Quantisation of Charge

How many electrons make up 1 coulomb of charge?

Answer

Formula: Q = ne ⇒ n = Q/e Given: Q = 1 C, e = 1.6 × 10⁻¹⁹ C n = 1 / (1.6 × 10⁻¹⁹) = 6.25 × 10¹⁸ electrons. Answer: 6.25 × 10¹⁸ electrons

Card 5Quantisation of Charge

Is a charge of 2.5e possible? Why or why not?

Answer

No. Charge is quantised in integer multiples of e (1.6 × 10⁻¹⁹ C). Since 2.5 is not an integer, 2.5e is not allowed. Only charges like 1e, 2e, 3e are possible.

Card 6Coulomb's Law

State Coulomb's Law.

Answer

The electrostatic force between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. Formula: F = k(q₁q₂

Card 7Coulomb's Law

Two charges of 6.0 × 10⁻¹⁰ C each are separated by 2.0 m. Find the Coulomb force between them.

Answer

Given: q₁ = q₂ = 6.0 × 10⁻¹⁰ C, r = 2.0 m, k = 9 × 10⁹ Nm²/C² F = k(q₁q₂)/r² = (9 × 10⁹) × (6.0 × 10⁻¹⁰)² / (2.0)² = (9 × 10⁹) × (3.6 × 10⁻¹⁹) / 4 = (3.24 × 10⁻⁹) / 4 = 8.1 × 10⁻¹⁰ N Answer: 8.1 × 10⁻

Card 8Coulomb's Law

Two charges q₁ = 16 μC and q₂ = 9 μC are 12 m apart. Find the force on q₁ due to q₂.

Answer

Given: q₁ = 16 × 10⁻⁶ C, q₂ = 9 × 10⁻⁶ C, r = 12 m, k = 9 × 10⁹ F = k(q₁q₂)/r² = (9 × 10⁹) × (16 × 10⁻⁶) × (9 × 10⁻⁶) / (12)² = (9 × 10⁹) × (1.44 × 10⁻¹⁰) / 144 = (1.296 × 10⁰) / 144 = 0.009 N Force o

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Frequently Asked Questions

What are the important topics in Electrical Charges and Fields for Telangana Open School (TOSS) Class 12 Physics?
Electrical Charges and Fields covers several key topics that are frequently asked in Telangana Open School (TOSS) Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Electrical Charges and Fields — Telangana Open School (TOSS) Class 12 Physics?
Understand the core concepts first, then work through the 52 practice questions available for this chapter. Revise formulas and definitions regularly, and use flashcards for quick recall before the exam.
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