Structure of the Atom
Telangana Open School (TOSS) · Class 12 · Physics
Flashcards for Structure of the Atom — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Structure of the Atom? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 12 students started this chapter today
What was the main observation in Rutherford's α-particle scattering experiment?
Answer
Most α-particles passed through the gold foil with little deflection, but a few were deflected at large angles (some even by 180°). This indicated that the positive charge and mass of the atom are con…
Why couldn't Thomson’s plum pudding model explain large-angle scattering of α-particles?
Answer
In Thomson’s model, positive charge is spread uniformly. Such a diffuse charge cannot produce strong repulsive forces needed for large-angle deflections. Only a concentrated positive charge (nucleus) …
State the key postulates of Bohr’s atomic model.
Answer
1. Electrons revolve in stable orbits without radiating energy. 2. Only orbits where angular momentum = nh/2π are allowed. 3. Energy is emitted or absorbed when electrons jump between orbits: ΔE = hν.
Calculate the radius of the first orbit of hydrogen atom (Bohr radius).
Answer
Formula: r₁ = (ε₀h²)/(πme²) Substitute values: m = 9.11×10⁻³¹ kg, e = 1.6×10⁻¹⁹ C, h = 6.626×10⁻³⁴ Js, ε₀ = 8.85×10⁻¹² C²/N·m² r₁ ≈ 5.3×10⁻¹¹ m = 0.53 Å…
What is the radius of the third orbit in a hydrogen atom?
Answer
Using rₙ = n²a₀, where a₀ = 0.53 Å For n = 3: r₃ = 9 × 0.53 = 4.77 Å…
Find the velocity of an electron in the second orbit of hydrogen atom.
Answer
Formula: vₙ = (Ze²)/(2ε₀nh) For hydrogen (Z=1), n=2: v₂ = (1.6×10⁻¹⁹)² / (2 × 8.85×10⁻¹² × 2 × 6.626×10⁻³⁴) ≈ 1.09×10⁶ m/s…
What is the energy of an electron in the second orbit of hydrogen atom?
Answer
Formula: Eₙ = -13.6/n² eV For n = 2: E₂ = -13.6 / 4 = -3.4 eV…
An electron jumps from n=3 to n=1. Calculate the energy of the emitted photon.
Answer
E₁ = -13.6 eV, E₃ = -13.6/9 = -1.51 eV ΔE = E₃ - E₁ = (-1.51) - (-13.6) = 12.09 eV Photon energy = 12.09 eV…
+17 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Structure of the Atom for Telangana Open School (TOSS) Class 12 Physics?
How to score full marks in Structure of the Atom — Telangana Open School (TOSS) Class 12 Physics?
How many flashcards are available for Structure of the Atom?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Structure of the Atom
Practice Quiz
Test yourself with a quick quiz
Important Questions
Practice with board exam-style questions
Revision Notes
Key points for last-minute revision
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Concept Maps
See how topics connect visually
Study Plan
Step-by-step plan to ace this chapter
Syllabus
What topics to cover
NCERT Solutions
Every textbook question solved step by step
For serious students
Get the full Structure of the Atom chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for Telangana Open School (TOSS) Class 12 Physics.