Ray Optics and Optical Instruments
Telangana Open School (TOSS) · Class 12 · Physics
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What is the magnifying power of a simple microscope when the image is formed at the least distance of distinct vision?
Answer
The magnifying power is given by: $$ M = 1 + \frac{D}{f} $$ Where: - $ D = 25 \,\text{cm} $ (least distance of distinct vision) - $ f $ is the focal length of the convex lens. This formula applies …
A simple microscope has a focal length of 5 cm. Calculate its magnifying power when the image is formed at the least distance of distinct vision.
Answer
Given: - $ f = 5 \,\text{cm} $ - $ D = 25 \,\text{cm} $ Formula: $$ M = 1 + \frac{D}{f} $$ Step 1: Substitute values $$ M = 1 + \frac{25}{5} = 1 + 5 = 6 $$ Answer: The magnifying power is **6**.
Define angular magnification or magnifying power of an optical instrument.
Answer
Angular magnification (or magnifying power) is the ratio of the angle subtended by the image at the eye to the angle subtended by the object when placed at the least distance of distinct vision. $$ M…
What is the difference between linear magnification and angular magnification?
Answer
**Linear magnification** is the ratio of the size of the image to the size of the object: $$ m = \frac{\text{Image height}}{\text{Object height}} $$ **Angular magnification** is the ratio of angles …
What is normal adjustment in a simple microscope?
Answer
Normal adjustment occurs when the final image is formed at infinity. In this case, the object is placed at the focal point of the convex lens. The magnifying power is: $$ M = \frac{D}{f} $$ This se…
Calculate the magnifying power of a simple microscope of focal length 2.5 cm in normal adjustment.
Answer
Given: - $ f = 2.5 \,\text{cm} $ - $ D = 25 \,\text{cm} $ Formula for normal adjustment: $$ M = \frac{D}{f} $$ Step 1: Substitute values $$ M = \frac{25}{2.5} = 10 $$ Answer: The magnifying power i…
What are the two main components of a compound microscope?
Answer
The two main components are: 1. **Objective lens**: A convex lens with very short focal length and small aperture, placed close to the object. It forms a real, inverted, and magnified image of the ob…
Derive the expression for magnifying power of a compound microscope when the final image is at the least distance of distinct vision.
Answer
Let: - $ m_o = \frac{v_o}{u_o} $ → magnification by objective - $ m_e = 1 + \frac{D}{f_e} $ → magnification by eyepiece (simple microscope) Total magnifying power: $$ M = m_o \times m_e $$ $$ M = \f…
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