Wave Optics — Flashcards
Telangana Open School (TOSS) · Class 12 · Physics
30 flashcards for Wave Optics (Telangana Open School (TOSS) Class 12 Physics) to test yourself on key terms and facts. Sample: "State Huygens' principle."
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State Huygens' principle.
Answer
Each point on a wavefront acts as a source of secondary wavelets. The new wavefront at any later time is the forward envelope of these secondary wavelets. For example, when light passes through a narr…
What is the relationship between wavefront and direction of propagation?
Answer
The direction of propagation of a wave is perpendicular to the wavefront. For example, in a plane wave, the wavefronts are flat planes, and the light travels perpendicularly to these planes.
In Young's double-slit experiment, how is constructive interference produced on the screen?
Answer
Constructive interference occurs when the path difference between waves from the two slits is an integral multiple of the wavelength (nλ). This means the waves arrive in phase, crest to crest, resulti…
What are coherent sources? Can our eyes act as coherent sources?
Answer
Coherent sources emit light waves of the same frequency and constant phase difference. Our eyes cannot act as coherent sources because they do not emit light; they only receive it.
A beam of light of average wavelength 600 nm enters a glass prism and splits into wavelengths 384 nm, 589 nm, and 760 nm. Find the refractive index for each.
Answer
Using μ = λ_air / λ_medium: - For 384 nm: μ₁ = 600 / 384 = 1.56 - For 589 nm: μ₂ = 600 / 589 ≈ 1.02 - For 760 nm: μ₃ = 600 / 760 ≈ 0.79 Answer: 1.56, 1.02, 0.79…
Define fringe width in Young’s double-slit experiment. Derive its formula.
Answer
Fringe width (β) is the distance between two consecutive bright or dark fringes. Formula: β = λD / d Where λ = wavelength, D = slit-to-screen distance, d = slit separation. Example: If λ = 600 nm, D =…
What happens to the interference pattern if one slit is closed in Young’s experiment?
Answer
When one slit is closed, interference stops and diffraction occurs. Instead of alternate bright and dark fringes, we get a broad central maximum with dimmer secondary maxima on either side due to sing…
Calculate the path difference at a point 5 cm from the central axis if slit separation is 2 mm and screen distance is 100 cm.
Answer
Given: d = 2 mm = 0.002 m, D = 100 cm = 1 m, x = 5 cm = 0.05 m Path difference Δ = (d/D)x = (0.002 / 1) × 0.05 = 0.0001 m = 0.1 mm Answer: 0.1 mm…
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