Simple Harmonic Motion
Telangana Open School (TOSS) · Class 12 · Physics
Flashcards for Simple Harmonic Motion — Telangana Open School (TOSS) Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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What is periodic motion?
Answer
Periodic motion is a type of motion that repeats itself after equal intervals of time. The smallest interval after which the motion repeats is called the time period (T). Example: motion of the hands …
Define oscillatory motion. How is it different from periodic motion?
Answer
Oscillatory motion is a to-and-fro motion about a mean position. All oscillatory motions are periodic, but not all periodic motions are oscillatory. For example, the motion of Earth around the Sun is …
What is Simple Harmonic Motion (SHM)?
Answer
Simple Harmonic Motion is a type of oscillatory motion where the acceleration of the particle is directly proportional to its displacement from the mean position and is always directed towards it. Mat…
State the condition for a motion to be simple harmonic.
Answer
For a motion to be simple harmonic, the restoring force must be directly proportional to the displacement and opposite in direction: F = -kx. This leads to acceleration a = -(k/m)x = -ω²x.
A particle executes SHM with amplitude 5 cm and angular frequency 4 rad/s. Write the displacement equation assuming zero initial phase.
Answer
Given: A = 5 cm = 0.05 m, ω = 4 rad/s, φ = 0. Using: y(t) = A sin(ωt + φ) So, y(t) = 0.05 sin(4t) meters.
The displacement of a particle in SHM is given by x = 4 sin(3t + π/6) cm. Find its maximum velocity.
Answer
Given: x = 4 sin(3t + π/6) cm → A = 4 cm = 0.04 m, ω = 3 rad/s Maximum velocity v_max = Aω = 0.04 × 3 = 0.12 m/s. Answer: 0.12 m/s.
A particle in SHM has a maximum acceleration of 18 m/s² and amplitude 0.06 m. Find its angular frequency.
Answer
Formula: a_max = Aω² Given: a_max = 18 m/s², A = 0.06 m So, 18 = 0.06 × ω² → ω² = 18 / 0.06 = 300 → ω = √300 ≈ 17.32 rad/s. Answer: 17.32 rad/s.
What is the time period of a simple pendulum of length 1 m? (Take g = 9.8 m/s²)
Answer
Formula: T = 2π√(l/g) Given: l = 1 m, g = 9.8 m/s² T = 2π√(1/9.8) = 2π√(0.102) ≈ 2π × 0.319 ≈ 2.00 s. Answer: 2.00 seconds.
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