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Simple Harmonic Motion — Flashcards

Telangana Open School (TOSS) · Class 12 · Physics

30 flashcards for Simple Harmonic Motion (Telangana Open School (TOSS) Class 12 Physics) to test yourself on key terms and facts.

42 questions30 flashcards13 formulas & key relations5 concepts

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30 Flashcards·
Periodic MotionOscillatory MotionSimple Harmonic MotionConditions for SHMDisplacement in SHMVelocity in SHMAcceleration in SHMSimple Pendulum
Card 1Periodic Motion

What is periodic motion?

Answer

Periodic motion is a type of motion that repeats itself after equal intervals of time. The smallest interval after which the motion repeats is called the time period (T). Example: motion of the hands …

Card 2Oscillatory Motion

Define oscillatory motion. How is it different from periodic motion?

Answer

Oscillatory motion is a to-and-fro motion about a mean position. All oscillatory motions are periodic, but not all periodic motions are oscillatory. For example, the motion of Earth around the Sun is …

Card 3Simple Harmonic Motion

What is Simple Harmonic Motion (SHM)?

Answer

Simple Harmonic Motion is a type of oscillatory motion where the acceleration of the particle is directly proportional to its displacement from the mean position and is always directed towards it. Mat…

Card 4Conditions for SHM

State the condition for a motion to be simple harmonic.

Answer

For a motion to be simple harmonic, the restoring force must be directly proportional to the displacement and opposite in direction: F = -kx. This leads to acceleration a = -(k/m)x = -ω²x.

Card 5Displacement in SHM

A particle executes SHM with amplitude 5 cm and angular frequency 4 rad/s. Write the displacement equation assuming zero initial phase.

Answer

Given: A = 5 cm = 0.05 m, ω = 4 rad/s, φ = 0. Using: y(t) = A sin(ωt + φ) So, y(t) = 0.05 sin(4t) meters.

Card 6Velocity in SHM

The displacement of a particle in SHM is given by x = 4 sin(3t + π/6) cm. Find its maximum velocity.

Answer

Given: x = 4 sin(3t + π/6) cm → A = 4 cm = 0.04 m, ω = 3 rad/s Maximum velocity v_max = Aω = 0.04 × 3 = 0.12 m/s. Answer: 0.12 m/s.

Card 7Acceleration in SHM

A particle in SHM has a maximum acceleration of 18 m/s² and amplitude 0.06 m. Find its angular frequency.

Answer

Formula: a_max = Aω² Given: a_max = 18 m/s², A = 0.06 m So, 18 = 0.06 × ω² → ω² = 18 / 0.06 = 300 → ω = √300 ≈ 17.32 rad/s. Answer: 17.32 rad/s.

Card 8Simple Pendulum

What is the time period of a simple pendulum of length 1 m? (Take g = 9.8 m/s²)

Answer

Formula: T = 2π√(l/g) Given: l = 1 m, g = 9.8 m/s² T = 2π√(1/9.8) = 2π√(0.102) ≈ 2π × 0.319 ≈ 2.00 s. Answer: 2.00 seconds.

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Frequently Asked Questions

What are the important topics in Simple Harmonic Motion for Telangana Open School (TOSS) Class 12 Physics?
Key topics in Simple Harmonic Motion include Periodic and Oscillatory Motion, Simple Harmonic Motion (SHM), Key Terms in SHM, Examples of SHM. Study these first, then practise questions on each for the Telangana Open School (TOSS) Class 12 board exam.
How many flashcards are available for Simple Harmonic Motion?
There are 30 flashcards for Simple Harmonic Motion covering key definitions, facts and ideas. A few sample cards are shown on this page.
How should I revise Simple Harmonic Motion for the Telangana Open School (TOSS) Class 12 board exam?
Learn the core ideas first, then work through the 42 practice questions on Simple Harmonic Motion. Revise definitions regularly and use flashcards for quick recall before the exam.

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